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nexus9112 [7]
3 years ago
8

Solve the linear equation 31x + 29y = 33 29x + 31y = 27

Mathematics
1 answer:
Temka [501]3 years ago
6 0

Answer:

x = 2

y = -1

Step-by-step explanation:

Make the coefficient of x the same

Multiply the first equation by 29

31x + 29y = 33 becomes

899x + 841y = 957

Multiply the second equation by 31

29x + 31y = 27 becomes

899x + 961y = 837

Subtract the equations

(899x + 841y) - (899x + 961y) = 957 - 837

(899x - 899x) + (841y - 961y) = 120

841y - 961y = 120

-120y = 120

y = 120/-120 = -1

Substitute the value of y into both equations to find the value of x and check its right.

31x + 29y = 33

31x + 29(-1) = 33

31x - 29 = 33

31x = 33 + 29

31x = 62

x = 62/31 = 2

29x + 31y = 27

29x + 31(-1) = 27

29x - 31 = 27

29x = 27 + 31

29x = 58

x = 58/29 = 2

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dolphi86 [110]

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The required polynomial is P(x)=x^4-10x^3+46x^2-96x+72.

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If a polynomial has degree n and c_1,c_2,...,c_n are zeroes of the polynomial, then the polynomial is defined as

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3 years ago
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sergey [27]
Hello,


The answer to this problem is, C.

4 minus the quotient of a number and 3



Hope this helps!
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