Answer:
1 ≥ t ≤ 3
Step-by-step explanation:
Given
h(t) = -16t² + 64t + 4
Required
Determine the interval which the bar is at a height greater than or equal to 52ft
This implies that
h(t) ≥ 52
Substitute -16t² + 64t + 4 for h(t)
-16t² + 64t + 4 ≥ 52
Collect like terms
-16t² + 64t + 4 - 52 ≥ 0
-16t² + 64t - 48 ≥ 0
Divide through by 16
-t² + 4t - 3 ≥ 0
Multiply through by -1
t² - 4t + 3 ≤ 0
t² - 3t - t + 3 ≤ 0
t(t - 3) -1(t - 3) ≤ 0
(t - 1)(t - 3) ≤ 0
t - 1 ≤ 0 or t - 3 ≤ 0
t ≤ 1 or t ≤ 3
Rewrite as:
1 ≥ t or t ≤ 3
Combine inequality
1 ≥ t ≤ 3
Remember that complementary angles add to 90 degrees.
so therefor, you can find the complement of m<A by solving
90 - 77 = A
A = 13 degrees
^^^ This explains the second part.
The compliment of a compliment can be found by subtracting the known compliment from 90 :)
Answer:
y=5x+31
Step-by-step explanation:
y=mx+b
1=(-6*5)+b
1=-30+b
31=b
y=5x+31
(5*-6)+31
-30+31
1
you can also graph a line on desmos
