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yKpoI14uk [10]
2 years ago
15

WILL MARK BRAINIEST IF RIGHT

Mathematics
2 answers:
deff fn [24]2 years ago
7 0
I think it’s c 20/29
Art [367]2 years ago
5 0

Answer:

Is it C. 20/29

Step-by-step explanation:

because 20 and 29 are right next to it.

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Work that is unpaid is called what
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An internship or apprenticeship
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The manager of a sporting goods store ordered 256 packages of football cards to be shipped to the store there are 24 cards in ea
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He ordered 6144 football cards
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Given f(x) = (lnx)^3 find the line tangent to f at x = 3
kirill [66]
Explanation

We must the tangent line at x = 3 of the function:

f(x)=(\ln x)^3.

The tangent line is given by:

y=m*(x-h)+k.

Where:

• m is the slope of the tangent line of f(x) at x = h,

,

• k = f(h) is the value of the function at x = h.

In this case, we have h = 3.

1) First, we compute the derivative of f(x):

f^{\prime}(x)=\frac{d}{dx}((\ln x)^3)=3*(\ln x)^2*\frac{d}{dx}(\ln x)=3*(\ln x)^2*\frac{1}{x}=\frac{3(\ln x)^2}{x}.

2) By evaluating the result of f'(x) at x = h = 3, we get:

m=f^{\prime}(3)=\frac{3}{3}*(\ln3)^2=(\ln3)^2.

3) The value of k is:

k=f(3)=(\ln3)^3

4) Replacing the values of m, h and k in the general equation of the tangent line, we get:

y=(\ln3)^2*(x-3)+(\ln3)^3.

Plotting the function f(x) and the tangent line we verify that our result is correct:

Answer

The equation of the tangent line to f(x) and x = 3 is:

y=(\ln3)^2*(x-3)+(\ln3)^3

6 0
1 year ago
Suppose f(x) = x2 and g(x) = (3x)2. Which statement best compares the graph
Ksenya-84 [330]

Answer:

Step-by-step explanation:

Please use " ^ " to indicate exponentiation:  f(x) = x^2 and g(x) = (3x)^2.

g(x) can be rewritten as 9x^2.

The graph of g(x) is only one ninth as wide as that of f(x).

Next time please share the possible answer choices.  Thank you.

6 0
3 years ago
1. The coordinates of the vertices of parallelogram RMBS are R(–4, 5), M(1, 4), B(2, –1), and S(–3, 0). Using the diagonals, pro
Whitepunk [10]
First, plot the points. Point R would be somewhere in the second Quadrant, point M would be in the first quadrant 1, point B would be in the fourth quadrant, and point S would be on the negative y-axis. A property of rhombi is that their diagonals are perpendicular. One would need to calculate the slopes of the diagonals and determine whether or not they are perpendicular. Lines are perpendicular if and only if their slopes are opposite reciprocals. Example: 2 and -0.5
Formulas needed:
Slope formula:
\frac{ y_{2}- y_{1}  }{ x_{2} - x_{1} }

The figure would look kinda like this:
      R
                  M
  
          S
                       B
 Diagonals are segment RB and segment SM
So, your slope equations would look like this:
 \frac{-1-5}{2-(-4)}
and
\frac{4-(-3)}{1-0}
Slope of RB= -1
Slope of SM=7
Not a rhombus, slopes aren't perpendicular. But this figure may very well be a parallelogram
7 0
3 years ago
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