I hope the choices for the numerators of the solutions are given.
I am showing the complete work to find the solutions of this equation , it will help you to find an answer of your question based on this solution.
The standard form of a quadratic equation is :
ax² + bx + c = 0
And the quadratic formula is:
x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
So, first step is to compare the given equation with the above equation to get the value of a, b and c.
So, a = 10, b = -19 and c = 6.
Next step is to plug in these values in the above formula. Therefore,




So, 

So, 
Hope this helps you!
Answer:
At most Mr.Gengel can cut at most 13 pieces with half a foot left.
Answer:
0.01
Step-by-step explanation:
It is easy try to figure it.
If you did not figure it out the answer is
A. I think is 24 not sure.
B. I think it is 18 not sure.
Answer:
<em>y ≥ x - 2, and x + 2y < 4 ; Option C</em>
Step-by-step explanation:
Consider the y - intercept and slope of 1 of these given lines,

From this we can formulate the equation of 1 line;

Now consider the y - intercept and slope of the remaining line;

This creates a line with the equation as such;

From this we see that the solution of the system is such;
<em>Solution ; y ≥ x - 2, and x + 2y < 4 ; Option C</em>