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2 years ago

5

Enter the equation of the line in slope-intercept form.

1 answer:

raketka [301]2 years ago

4 0

Answer:

y = 5x-14

Step-by-step explanation:

We should use point-slope form to form our equation:

y-1 = 5(x-3)

y-1 = 5x-15

y = 5x-14

Our equation is now in slope-intercept form.

HTH :)

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I need help with number 12

mestny [16]

(r - s)³ + r²
= (-3 - (-4))³ + (-3)²
= (-3 + 4)³ + 9
= 1³ + 9
= 1 + 9
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2 years ago

I don't understand this factorisation <br> a2+ 4a+3

Tomtit [17]

Answer:

$\boxed{\sf (a + 3)(a + 1)}$

Step-by-step explanation:

$\sf Factor \: the \: following: \\ \sf \implies {a}^{2} + 4a + 3 \\ \\ \sf The \: factors \: of \: 3 \: that \: sum \: to \: 4 \\ \sf are \: 3 \: and \: 1. \\ \\ \sf So, \\ \sf \implies {a}^{2} + (3 + 1)a + 3 \\ \\ \sf \implies {a}^{2} + 3a + a + 3 \\ \\ \sf \implies a(a + 3) + 1(a + 3) \\ \\ \sf \implies (a + 3)(a + 1)$

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2 years ago

Easy variable question pls help

svet-max [94.6K]

Answer:

z = -4 1/2

Step-by-step explanation:

1. First change the mixed fractions to improper fractions so it's easier

$\frac{16}{5\\}/(z-\frac{1}{2}) = \frac{8}{3}/(z+\frac{1}{3})$

2. Simplify

$\frac{32}{5(2z-1)} = \frac{8}{3z+1}$

3. Cross multiply

$32(3z+1) = 5(2z-1) * 8$

4. Simplify again (distributive property)

$32(3z+1) = 40(2z-1)$

5. Distributive property

$32(3z+1) -> 96z+32$

$40(2z-1) -> 80z-40$

$96z+32=80z-40$

6. Subtract 32 from both sides

$96z+32-32 = 80z-40-32$

7. Simplify

$96z = 80z-72$

8. Subtract 80 from both sides

$96z-80z=80z-72-80z$

9. Simplify

$16z=-72$

10. Divide both sides by 16

$\frac{16z}{16}=\frac{-72}{16}$

11. Simplify

$z=-\frac{9}{2} -> also = -4\frac{1}{2}$

Sorry if it was too long but hope this helps! :)

And also try using symbolab cuz it gives step by step explanations it's really good!

7 0

2 years ago

What is bigger 100 inches or 3 yards+1 feet

RoseWind [281]

3 yards + 1 foot would be bigger than 100 inches

8 0

2 years ago

Read 2 more answers

Use Stokes' Theorem to evaluate C F · dr where C is oriented counterclockwise as viewed from above. F(x, y, z) = xyi + 5zj + 7yk

REY [17]

By Stokes' theorem,

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

where $S$ is the surface with $C$ as its boundary. The curl is

$\nabla\times\vec F(x,y,z)=2\,\vec\imath-x\,\vec k$

Parameterize $S$ by

$\vec\sigma(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+(8-u\cos v)\,\vec k$

with $0\le u\le9$ and $0\le v\le2\pi$ . Then take the normal vector to $S$ to be

$\vec\sigma_u\times\vec\sigma_v=u\,\vec\imath+u\,\vec k$

Then the line integral is equal to the surface integral,

$\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^9(2\,\vec\imath-u\cos v\,\vec k)\cdot(u\,\vec\imath+u\,\vec k)\,\mathrm du\,\mathrm dv$

$\displaystyle=\int_0^{2\pi}\int_0^9(2u-u^2\cos v)\,\mathrm du\,\mathrm dv=\boxed{162\pi}$

7 0

2 years ago