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3 years ago

Simplify the following expression, show all work you did to get the results

Mathematics

1 answer:

777dan777 [17]3 years ago

5 0

Answer:

(sqrt(7))/3 or decimal 0.8819171036881968635005385845464201419034197276941500601227781530...

Step-by-step explanation:

Simplify the following:

(sqrt(14))/(sqrt(18))

Hint: | Simplify radicals.

sqrt(18) = sqrt(2×3^2) = 3 sqrt(2):

(sqrt(14))/(3 sqrt(2))

Hint: | Multiply numerator and denominator of (sqrt(14))/(3 sqrt(2)) by sqrt(2).

Rationalize the denominator. (sqrt(14))/(3 sqrt(2)) = (sqrt(14))/(3 sqrt(2))×(sqrt(2))/(sqrt(2)) = (sqrt(14) sqrt(2))/(3×2):

(sqrt(14) sqrt(2))/(3×2)

Hint: | Multiply 3 and 2 together.

3×2 = 6:

(sqrt(14) sqrt(2))/6

Hint: | For a>=0, sqrt(a) sqrt(b) = sqrt(a b). Apply this to sqrt(14) sqrt(2).

sqrt(14) sqrt(2) = sqrt(14×2):

(sqrt(14×2))/6

Hint: | Multiply 14 and 2 together.

14×2 = 28:

(sqrt(28))/6

Hint: | Simplify radicals.

sqrt(28) = sqrt(2^2×7) = 2 sqrt(7):

(2 sqrt(7))/6

Hint: | In (2 sqrt(7))/6, divide 6 in the denominator by 2 in the numerator.

2/6 = 2/(2×3) = 1/3:

Answer: (sqrt(7))/3

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4 years ago

A company developing a new cellular phone plan intends to market their new phone to customers who use text and social media ofte

Ber [7]

Answer:

A customer who sends 78 messages per day would be at 99.38th percentile.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Average of 48 texts per day with a standard deviation of 12.

This means that $\mu = 48, \sigma = 12$

a. A customer who sends 78 messages per day would correspond to what percentile?

The percentile is the p-value of Z when X = 78. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{78 - 48}{12}$

$Z = 2.5$

$Z = 2.5$ has a p-value of 0.9938.

0.9938*100% = 99.38%.

A customer who sends 78 messages per day would be at 99.38th percentile.

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3 years ago

An experimenter is studying the effects of temperature, pressure, and type of catalyst on yield from a certain chemical reaction

irga5000 [103]

Answer:

0.0154

Step-by-step explanation:

a) #Possible experimental run=#Temp x #pres x #cat=3x5x6=90

b) #Possible experimental run=(Temp. lowest) x 2.pres x #cat=1x2x6=12

c) C="different catalyst is used on each run"

In the first, I can choice 6 of 6 catalysts, in the second 5 of 6,...

then: P(C) = 6/6 x 5/6 x 4/6 x 3/6 x 2/6 x 1/6 = 5/324 = 0.0154

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4 years ago

What is −5/8 ÷ 9/10 in fraction form.

ira [324]

Answer:

exact form os -25/36

Step-by-step explanation:

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3 years ago

Read 2 more answers

A man ordered 5 times as many boxes of ballpoint pens as boxes of felt-tip pens. Ballpoint pens cost $4.33 per box, and felt-poi

Brrunno [24]

Using equation, He bought 3 boxes of ballpoint pens and 15 boxes of felt-tip pens

<h3>How to find the boxes of each type of pen using equation?</h3>

let

x = number of boxes of ballpoint pens

y = number of boxes of felt-tip pens

Therefore, the situation will form an equation.

x = 5y

Hence,

4.33x + 3.42y = 75.21,

4.33(5y) + 3.42y = 75.21

21.65y + 3.42y = 75.21

25.07y = 75.21

y = 75.21 / 25.07

y = 3

x = 5(3) = 15

Hence, he bought 3 boxes of ballpoint pens and 15 boxes of felt-tip pens

learn more on equation here: brainly.com/question/13189687

#SPJ1

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2 years ago

Simplify the following expression, show all work you did to get the results​

Simplify the following expression, show all work you did to get the results