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IRISSAK [1]
3 years ago
6

FREE BRAINLIEST

Mathematics
2 answers:
Bond [772]3 years ago
7 0

Answer:

J,S,U,N

Step-by-step explanation:

Jupiter stern Uranus and Neptune

nirvana33 [79]3 years ago
6 0

Answer:

Jupiter, Saturn, Uranus, and Neptune

Step-by-step explanation:

yes

You might be interested in
Which choice is equivalent to the expression below when y2 0?<br> √y^2 + √16y^3 – 4y√y
DanielleElmas [232]

Answer:

Option C.

Step-by-step explanation:

We start with the expression:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y}

where y > 0. (this allow us to have y inside a square root, so we don't mess with complex numbers)

We want to find the equivalent expression to this one.

Here, we can do the next two simplifications:

\sqrt{16*y^3} = \sqrt{16} \sqrt{y^3} = 4*\sqrt{y^3}

And:

y*\sqrt{y} = \sqrt{y^2} *\sqrt{y} = \sqrt{y^2*y} = \sqrt{y^3}

If we apply these two to our initial expression, we can rewrite it as:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y}

\sqrt{y^3}  + 4*\sqrt{y^3} - 4\sqrt{y^3} = \sqrt{y^3}

Here we can use the second simplification again, to rewrite:

\sqrt{y^3} = y*\sqrt{y}

So, concluding, we have:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y} = y*\sqrt{y}

Then the correct option is C.

8 0
3 years ago
37 % of $2927 is what
velikii [3]

Answer:

$1,082.99

Step-by-step explanation:

2927 * 0.37 = 1,082.99

3 0
3 years ago
Repost, algebra help needed please
Rom4ik [11]

Answer:

y- intercept = \frac{1}{2}

Step-by-step explanation:

Given

f(x) = \frac{1}{2} (6)^{x}

To find the y- intercept let x = 0 , then

f(0) = \frac{1}{2} (6)^{0} [ 6^{0} = 1 ]

      = \frac{1}{2} × 1 = \frac{1}{2} ← y- intercept

5 0
3 years ago
​If Alfie tosses the paper cup more times, what is the expected ​number of times that the cup will land on its side?
IRINA_888 [86]

Question:

Alfie tossed a paper cup in the air 150 times and recorded the side it landed on.

     Right side up = 60         Upside down = 53             Side = 37

If Alfie tosses the paper cup 100 more times what is the expected number of times the cup will land on its side?

 

Answer:

The expected number of times the cup will land on its side is 25 times

Step-by-step explanation:

Given

Right = 60

Upside\ down = 53

Side = 37

Required

First, we calculate the probability of landing on side

P(Side) = \frac{n(Side)}{Total}

P(Side) = \frac{37}{150}

P(Side) = 0.247

Next, we calculate the expected value; E(x) using:

E(x) = n * P(x)

When tossed 100  more times:

n = 100 and P(x) = P(Side) = 0.247

So:

E(x) = 100 * 0.247

E(x) = 24.7

E(x) = 25 --- approximated

<em>Hence, it is expected that it will land on its side 25 times</em>

3 0
3 years ago
3-6x (34 divided by3º)2
lora16 [44]

Answer:

3^-6(81)^2=3^-6(6561)=9 which is 3^2

7 0
3 years ago
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