In fraction how too solve 2/8=4

I need this fast guys. This is due tomorrow help a fellow comrade out

gavmur [86]

So whats the answer. please help me I got a test of this

3 0

3 years ago

Need help with math

podryga [215]

I have no idea math should have been working hade books bye sorry

4 0

3 years ago

One measure of an athlete’s ability is the height of his or her vertical leap. Many professional basketball players are known fo

almond37 [142]

Answer:

(1) P( $\bar X$ < 26 inches) = 0.0436

(2) P(27.5 inches < $\bar X$ < 28.5 inches) = 0.2812

Step-by-step explanation:

We are given that the mean vertical leap of all NBA players is 28 inches. Suppose the standard deviation is 7 inches and 36 NBA players are selected at random.

Firstly, Let $\bar X$ = mean vertical leap for the 36 players

Assuming the data follows normal distribution; so the z score probability distribution for sample mean is given by;

Z = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean vertical leap = 28 inches

$\sigma$ = standard deviation = 7 inches

n = sample of NBA player = 36

(1) Probability that the mean vertical leap for the 36 players will be less than 26 inches is given by = P( $\bar X$ < 26 inches)

P( $\bar X$ < 26) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{26-28}{\frac{7}{\sqrt{36} } }$ ) = P(Z < -1.71) = 1 - P(Z $\leq$ 1.71)

= 1 - 0.95637 = 0.0436

(2) <em>Now, here sample of NBA players is 26 so n = 26.</em>

Probability that the mean vertical leap for the 26 players will be between 27.5 and 28.5 inches is given by = P(27.5 inches < $\bar X$ < 28.5 inches) = P( $\bar X$ < 28.5 inches) - P( $\bar X$ $\leq$ 27.5 inches)

P( $\bar X$ < 28.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{28.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z < 0.36) = 0.64058 {using z table}

P( $\bar X$ $\leq$ 27.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{27.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z $\leq$ -0.36) = 1 - P(Z < 0.36)

= 1 - 0.64058 = 0.35942

Therefore, P(27.5 inches < $\bar X$ < 28.5 inches) = 0.64058 - 0.35942 = 0.2812

6 0

3 years ago

Explain how to find the estimated sum of <br><br><br> 5<br> 8<br> +<br> 2<br> 9<br> .

mina [271]

The estimated sum of the numbers fifty-eight (58) and twenty-nine (29) is equal to ninety (90).

<h3>What is the difference between a regular sum and an estimated sum?</h3>

In an estimated sum, the numbers are rounded; on the other hand, in a regular sum, the numbers are not changed.

<h3>What is the estimated sum of 58 and 29?</h3>

1. Round the numbers:

58 = 60 as this number is nearest to 60 than to 58.
29= 30 because of the same reason explained above.

2. Add the rounded numbers:

60 + 30 = 90

Learn more about estimated sum in: brainly.com/question/660898

#SPJ1

7 0

2 years ago

What two numbers have a difference of 5 and a product of 3.36

iris [78.8K]

X-y=5
xy=3.36
add y to both sides on first
x=5+y
sub that in other eqation
(5+y)y=3.36
expand
y^2+5y=3.36
minus 3.36 both sides
y^2+5y-3.36=0
use quadratic formula

for
ay^2+by+c=0
$y= \frac{-b+/- \sqrt{b^2-4ac} }{2a}$
for 1y^2+5y-3.36
$y= \frac{-5+/- \sqrt{5^2-4(1)(-3.36)} }{2(1)}$
$y= \frac{-5+/- \sqrt{25+13.44} }{2}$
$y= \frac{-5+/- \sqrt{38.44} }{2}$
$y= \frac{-5+/- 6.2}{2}$
y=-2.5+/-3.1
y=5.6 or 0.6
sub back

x=y+5
so
x=10.6 or 5.6

the numbers are either 10.6 and 5.6 or 0.6 and 5.6
wait,but 10.6 and 5.6 don't multiply to get 3.36 so that is an extrainiesous answer

answer is 0.6 and 5.6

7 0

3 years ago