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ratelena [41]
3 years ago
12

Find the value of x in a triange..which x -10+2x+20+x+20

Mathematics
2 answers:
Elenna [48]3 years ago
5 0

Step-by-step explanation:

40-10+3X

30+3X

30=3X

10=X

statuscvo [17]3 years ago
4 0

ANSWER:

-10+2x+20+x+20

-10+20+20+2x+x

30 = 3x

10 = x

~batmans wife dun dun dun...

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H(t) = 0 for t = 7 and for t = -2.

It is reasonable for the time to be positive, 7 seconds.

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3 years ago
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Given the system of inequalities below: -3x - y < 12 2x + 3y ≥ 9 Give the coordinates of three points that are members of the
earnstyle [38]

Answer:

The coordinates of the points that are members of the solution set

(-3,7), (0,4) and (2,3)

Step-by-step explanation:

we have

-3x-y< 12 ----> inequality A

The solution of the inequality A is the shaded area above the dashed line

2x+3y\geq 9 ----> inequality B

The solution of the inequality B is the shaded area above the solid line

The solution of the system of inequalities is the shaded area between the dashed line and the solid line

see the attached figure

Remember that,

If a ordered pair is a solution of the system of inequalities, then the ordered pair must be in the shaded area of the solution

Plot the points

(-3, 7), (-3, -7), (3,-7), (-4,-0), (0,-4), (0,4), (2,3), (-2,3), (2,-3)

therefore

The coordinates of the points that are members of the solution set

(-3,7), (0,4) and (2,3)

3 0
4 years ago
Please help FAST I need the answer along with you explaining the steps so I can get it thanks! I’ll give Brainlist also!
kupik [55]

Answer:

The equation of required line is: \mathbf{5x-8y+34=0}

Step-by-step explanation:

We need to write equation in the form Ax+By+C=0 of the line parallel to 5x-8y+12=0 and through the point (-2,3)

First we need to find slope and y-intercept of the required line.

Using equation of line  5x-8y+12=0 to find slope.

Since the given line and required lines are parallel there slope is same.

Writing equation in slope intercept form: y=mx+b where m is slope.

5x-8y+12=0 \\-8y=-5x-12\\\frac{-8y}{-8y}=\frac{-5x}{-8}-\frac{12}{-8}\\y=\frac{5}{8}x+\frac{3}{4}

So, the slope m = 5/8

The slope of required line is m=\frac{5}{8}

Now finding y-intercept using slope m=\frac{5}{8} and point(-2,3)

y=mx+b\\3=\frac{5}{8}(-2)+b\\3=\frac{-5}{4}+b\\b=3+\frac{5}{4}\\b=\frac{3*4+5}{4}\\b=\frac{12+5}{4}\\b=\frac{17}{4}

So, the equation of required line having slope m=\frac{5}{8}  and y-intercept b=\frac{17}{4}

y=mx+b\\y=\frac{5}{8}x+\frac{17}{4}\\y=\frac{5x+17*2}{8}\\y= \frac{5x+34}{8}  \\8y=5x+34\\5x-8y+34=0

So, The equation of required line is: \mathbf{5x-8y+34=0}

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The equation for line E is x = 8.
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Is there a x=-2 in these equations
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plug in the x for all of those to find y


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