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ratelena [41]
3 years ago
12

Find the value of x in a triange..which x -10+2x+20+x+20

Mathematics
2 answers:
Elenna [48]3 years ago
5 0

Step-by-step explanation:

40-10+3X

30+3X

30=3X

10=X

statuscvo [17]3 years ago
4 0

ANSWER:

-10+2x+20+x+20

-10+20+20+2x+x

30 = 3x

10 = x

~batmans wife dun dun dun...

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Please answer it for me or show me how to do it? I will mark you branliast answer !!
klasskru [66]

Answer:

25

Step-by-step explanation:

If HI and IJ are both the same and meet at the same point, the triangles would be the same.

7 0
4 years ago
The two polygons above are similar. The scale factor of the smaller polygon to the larger polygon is 3. The area of the smaller
Softa [21]
You would think it was 3 * 12 = 36. Not so. All polygons have to be broken down into some figure that will give 2 dimensions that are at right angles to each other. That would mean that
d1 * d2 = Area for the small polygon
3d1 * 3d2 = area of the larger polygon

What that means is that the area of the larger one is 9 times the smaller one.
Area large = 12 * 9 = 108 square units. <<<<< answer.

If you find this hard to be leave try it with a square.
Suppose you have a square (the small one) that is 3 cm by 3 cm
The small one has an area of 3*3 cm^2 = 9 cm

Now you have another square that is 3 times larger. That means that each side is 3*3 = 9
So s = 9
Area = s^2
Area = 9^2 = 81 cm^2
81 is 9 times larger than 9 just as you would think. 


4 0
3 years ago
Two vectors a and b have magnitudes 2√2 and 9 respectively. Also, a⋅b=18. Find the angle between a and b to the nearest whole de
ivann1987 [24]

Answer:

The angle is the 32 is the angle

5 0
3 years ago
The sum of an arithmeit cprogression consisting of 20 positive integer terms with positive common difference is equal to 2020. (
Rufina [12.5K]

Answer:

a) possible progressions are 5

b) the smallest and largest possible values of the first term are 16 and 82

Step-by-step explanation:

<u>Sum of terms:</u>

  • Sₙ = n/2(a₁ + aₙ) = n/2(2a₁ + (n-1)d)
  • S₂₀ = 20/2(2a₁ + 19d) = 10(2a₁ + 19d)
  • 2020 = 10(2a₁ + 19d)
  • 202 = 2a₁ + 19d

<u>In order a₁ to be an integer, d must be even number, so d = 2k</u>

  • 202 = 2a₁ + 38k
  • 101 = a₁ + 19k

<u>Possible values of k= 1,2,3,4,5</u>

  • k = 1 ⇒ a₁ = 101 - 19 = 82
  • k = 2 ⇒ a₁ = 101 - 38 = 63
  • k = 3 ⇒ a₁ = 101 - 57 = 44
  • k = 4 ⇒ a₁ = 101 - 76 = 25
  • k = 5 ⇒ a₁ = 101 - 95 = 16

<u>As per above, </u>

  • a) possible progressions are 5
  • b) the smallest and largest possible values of the first term are 16 and 82
6 0
3 years ago
Pls help me this is so hard
Mama L [17]

Answer:

She is not breaking even. The discounted price is .84t, which is less than t.

Step-by-step explanation:

Retail price= 1.4

1.4×.4= .56

40% of 1.4 is .56

Subtract 40% of 1.4 from the retail price because she is marking down.

(1.4)-(.56)=.84

So the discounted price is .84t

This problem is difficult because we don't know if she sold any tea by the retail price and if she did how much did she sell.

5 0
3 years ago
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