9514 1404 393
Answer:
$96
Step-by-step explanation:
Morgan worked 48 -40 = 8 hours of overtime. The pay for each of those hours is 1.5×$8 = $12.
Morgan earned (8 h)×($12/h) = $96 in overtime pay.
12/3x(11) that is the simplest form you can get it to
Answer:
Arithmetic density.
Step-by-step explanation:
The correct answer is arithmetic density. This is because for a country, it is also known as real density and it's defined as the number of people per unit area of total land in that country.
Thus, the population of a country divided by its area determines its arithmetic density
The correct answer is: " √x − <span>2√b " .
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The "conjugate" of " √x + 2√b " is: " √x − 2√b " .
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Explanation:
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In an expression with 2 (TWO) terms; that is, in a "binomial expression",
the "conjugate" of that expression refers to that very expression — with the "sign" in between those two terms—"reverse" (e.g. "minus" becomes "plus" ; or, "plus" becomes "minus" .) .
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→ So: We are given: " <span>√x + 2√b " .
</span>
→ Note that this is a "binomial expression" ;
→ that is, there are 2 (TWO) terms: " <span>√x " ; and: " 2√b " .
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To find the "conjugate" of the given binomial expression:
</span>→ " <span>√x + 2√b " ;
</span>→ We simply change the "+" {plus sign} to a "<span>−" {minus sign} ; and rewrite:
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</span>→ " √x − 2√b " ;
→ which is the "conjugate" ; and is the correct answer:
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→ " √x − 2√b " ; is the "conjugate" of the expression: " <span>√x + 2√b " .
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</span>→ {that is: " √x − 2√b " ; is the conjugate.}.
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Step-by-step explanation:
According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:
![\displaystyle Phase\:[Horisontal]\:Shift → \frac{-\frac{2}{3}π}{2} = -\frac{π}{3} \\ Period → \frac{2}{2}π = π](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7B-%5Cfrac%7B2%7D%7B3%7D%CF%80%7D%7B2%7D%20%3D%20-%5Cfrac%7B%CF%80%7D%7B3%7D%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B2%7D%7B2%7D%CF%80%20%3D%20%CF%80)
Therefore we have our answer.
Extended Information on the trigonometric function
![\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Vertical%5C%3AShift%20%E2%86%92%20D%20%5C%5C%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7BC%7D%7BB%7D%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B2%7D%7BB%7D%CF%80%20%5C%5C%20Amplitude%20%E2%86%92%20%7CA%7C)
NOTE: Sometimes, your vertical shift might tell you to shift your graph below or above the <em>midline</em><em> </em>where the amplitude is.
I am joyous to assist you anytime.
