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3 years ago

BRAINLIESTT ASAP! PLEASE HELP ME :)

Mathematics

2 answers:

Elenna [48]3 years ago

4 0

The answer to your question is 2+34equal 2600

antiseptic1488 [7]3 years ago

3 0

Step-by-step explanation:

$\displaystyle y = Acos(Bx - C) + D$

According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:

$\displaystyle Phase\:[Horisontal]\:Shift → \frac{-\frac{2}{3}π}{2} = -\frac{π}{3} \\ Period → \frac{2}{2}π = π$

Therefore we have our answer.

Extended Information on the trigonometric function

$\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|$

NOTE: Sometimes, your vertical shift might tell you to shift your graph below or above the midline where the amplitude is.

I am joyous to assist you anytime.

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Farmer George is painting 3 chicken coops. He started painting this morning. Now he only has 3/4 of a chicken coop left to paint

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3 years ago

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The table represents a linear function.

Illusion [34]

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3 years ago

What is the value of y if (4y + 8) - (7y - 12) = 11? (PLEASE ANSWER + 10 POINTS!!!!)?

lyudmila [28]

Hello!

(4y + 8) - (7y - 12) = 11 is 1(4y + 8) - 1(7y - 12) = 11

1(4y + 8) - 1(7y - 12) = 11 Given
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3 years ago

Simplify the expression by factoring, showing the steps in your work.

alexdok [17]

Given:

$$\frac{12 x^{2}+31 x+7}{16 x^{2}+8 x+1}$

To find:

The simplified expression by factoring.

Solution:

Let us factor the numerator:

$12 x^{2}+31 x+7$

31x can be written as 3x + 28x.

$=\left(12 x^{2}+3 x\right)+(28 x+7)$

Take 3x common in 1st two terms and 7 common in next two terms.

$=3 x(4 x+1)+7(4 x+1)$

Make sure the remaining terms in the both brackets must be same.

Now, take out common factor (4x + 1).

$=(4 x+1)(3 x+7)$

In the same way, factorize the denominator:

$16 x^{2}+8 x+1$

8x can be written as 4x + 4x.

$=(16 x^{2}+4 x)+(4x+1)$

Take 4x common in 1st two terms and 1 common in next two terms.

$=4x(4 x+1)+1(4x+1)$

Make sure the remaining terms in the both brackets must be same.

Now, take out common factor (4x + 1).

$=(4x+1)(4x+1)$

Substitute the terms we found for numerator and denominator:

$$\frac{12 x^{2}+31 x+7}{16 x^{2}+8 x+1}=\frac{(4 x+1)(3 x+7)}{(4 x+1)(4 x+1)}$

Cancel the common factors.

$$=\frac{3 x+7}{4 x+1}$

The simplified expression is $\frac{3 x+7}{4 x+1}$ .

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4 years ago

Can someone answer these? 2(4x+5)=8x+10 and 2(4v-9)-(3v-11)=-52

Irina18 [472]

For the first one, we will have to factor out the numbers. So 2 times 4x is 8x and 2 times 5 is 10. Our new expression will now be 8x + 10 = 8x + 10. Now, since these are equal, x must equal 1.

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3 years ago

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