All categories

2 years ago

PLEASE HURRY WILL GIVE BRAILIEST!!

Mathematics

2 answers:

zlopas [31]2 years ago

7 0

y=-3/4x-(15/2)
......................

gladu [14]2 years ago

6 0

<h3><em>Answer:</em></h3><h3><em>y + 1 = -5(x-4)</em></h3><h3><em>Explanation:</em></h3><h3><em>Point-slope form is shown here:</em></h3><h3><em>Since we have the value of one point and the slope, we can plug those into the formula:</em></h3><h3><em>y-(-1)=-5(x-4)</em></h3><h3><em>And we can simplify that to:</em></h3><h3><em>y + 1 = -5 (x-4)</em></h3><h3><em /></h3><h3><em>Hope this helps!</em></h3>

You might be interested in

Circle A has a radius of 6. Which circles

Galina-37 [17]

Answer: circle e, circle f

Step-by-step explanation:

4 0

3 years ago

The product of 5 and b

ArbitrLikvidat [17]

Product indicates multiplication. Therefore 5 x b = 5b

7 0

3 years ago

3. Lonnie has a gift card worth $600 for a local entertainment store. Movies cost $20 each and newly released video games cost $

Mandarinka [93]

Answer:

8 movies and 6 video games

Step-by-step explanation:

Given

$Gift\ Card = \$600$

$Movies =\ $20$

$Video\ Game = \$50$

$Minimum\ Items = 13$

Required

Determine the items Lonnie can afford

To solve this question, we make use of trial by error method by taking the options one at a time:

Option 1: 6 movies and 4 video games

<em>This option can not be considered because the number of items is not up to the minimum Lonnte must purchase.</em>

<em />

Option 2: 14 movies and 7 video games

$Cost = 14 * \$20 + 7 * \$50$

$Cost = \$280 + \$350$

$Cost = \$630$

<em>This option can not be considered because the cost of purchase is greater than Lonnte's worth of Gift card.</em>

<em />

Option 3: 2 movies and 10 video games

<em>This option can not be considered because the number of items is not up to the minimum Lonnte must purchase.</em>

<em />

Option 4: 8 movies and 6 video games

$Cost = 8 * \$20 + 6 * \$50$

$Cost = \$160 + \$300$

$Cost = \$460$

Hence, the correct option is <em>8 movies and 6 video games </em>

4 0

3 years ago

WILLL GIVE BRAINLIEST + 50 POINTS FOR HELP!!!!<br><br><br>PLZZZZZZ IM TIMED

andrew-mc [135]

First. y=2x
second d is correct
third is a

7 0

3 years ago

Read 2 more answers

Human visual inspection of solder joints on printed circuit boards can be very subjective. Part of the problem stems from the nu

olga_2 [115]

Answer:

The probability that the selected joint was judged to be defective by neither of the two inspectors is $P(A' n B' ) = 0.8855$

The probability that the selected joint was judged to be defective by inspector B but not by inspector A is $P(A' n B) =0.0403$

Step-by-step explanation:

From the question we are told that

The sample size is $n_s = 10000$

The number of outcome for inspector A is $n__{A}} = 742$

The number of outcome for inspector B is $n__{B}} = 745$

The number of joints judged defective by both inspector is $n(A u B) = 1145$

The the probability that the selected joint was judged to be defective by neither of the two inspectors is mathematically represented as

$P(A' n B' ) = 1 - P(A u B)$

Now

$P(A\ u \ B) = \frac{n(Au B)}{n_s }$

substituting values

$P(A\ u \ B) = \frac{1145}{ 10 000 }$

$P(A' n B' ) = 1 - \frac{1145}{10 000}$

$P(A' n B' ) = 0.8855$

the probability that the selected joint was judged to be defective by inspector B but not by inspector A is mathematically represented as

$P(A' n B) = P(A \ u \ B) -P(A)$

Now

$P(A) = \frac{n__{A}}{n_s}$

substituting values

$P(A) = \frac{742}{10 000}$

$P(A' n B) = \frac{1145}{10 000} - \frac{742}{10 000}$

$P(A' n B) =0.0403$

7 0

4 years ago