Unscramble thr words <br>1.Nsieg Wiev<br>2.Seeathdat ievw

When viewing data entered into a spreadsheet, the columns identify _____.?

AlexFokin [52]

The answer is : variables
When viewing data entered into a spreadsheet, the columns identify Variable. The variables later can be used on a formula to help you process any sort of data that is implemented within excels' formula system

3 0

4 years ago

Just five types of pointing device,list

posledela

Answer:

five types of pointing devices

Explanation:

Ponting devices

Pointing means point something and the pointing devices are the input /peripheral devices those are used to point the pointer on the screen. We do move cursor on the screen to open the files or any icon.

There are many types of pointing devices but these are quite common which are given below

Computer mouse
Finger on touch screen.
Joystick.
Leap Motion.
Light pen (pen)

1.Mouse

Mouse is most common type of input device that is used for pointing the data on the screen. We press it with our hands and keep pointing the things.

There are three types of mouse

optical mouse
wireless mouse
trackball mouse.

2. Finger on touch screen

In this type of movement the fingers are input devices those we use to see the movement of pointer on the screen and this is most common in this century.

3.Joystick.

Joystick is another input device to point the cursor but it is mostly used in games. Children can use it smartly so it is inculcated in games usually.

4. Leap Motion

The Leap Motion (LM) controller is a latest 3D sensing device for hand posture interaction with a computer. It is having the capability sense the location of the fingers of the hands, as well as the palm position.

5.Light Pen

this is another pointing device which is mostly used to highlight and select the data on the screen.

Note: All of these above pointing devices are most common used now a days. These devices are having new conventions day by day for the ease of user. This era is basically the era of IT ,so the use of computer must be so easy and conventional for the user so, the innovations and improvement in such devices is made side by side.

3 0

3 years ago

While working independently, you need to weigh your options on a topic. You research and analyze the topic so you can ensure you

Andrews [41]

I think this process would be Decision-Making, because the scenario is that you have to decide on what topic you are going to pick, based on research and what you think would be the best resolution. I don't think that Conflict resolution would be correct because there is no conflict and neither Negotiation nor Verbal Communication have anything to do with this, so i believe it's safe to assume the correct answer would be Decision Making.

8 0

3 years ago

Read 2 more answers

In cell E14, enter a date function that calculates the number of days between the Initial Deadline (cell E10) and the Date Recei

tatuchka [14]

Answer:

The formula to enter in E14 is as follows:

=DAYS(D14,$E$10)

Explanation:

Required

Formula to calculate the number of days between E10 and D14

The syntax to do this is:

=DAYS(end_date,start_date)

So, we have:

=DAYS(D14,E10)

The question requires a mix of relative and mixed references because cell E10 will be constant in calculating the difference for dates in other cells.

In other words, the initial date is constant for all

So, the update formula is:

=DAYS(D14,$E$10)

Notice the $ between in E10; this represents mixed referencing

When dragged to E15 till E68, the formulas in the respective cells will be:

=DAYS(D15,$E$10) .............................. =DAYS(D68,$E$10)

7 0

3 years ago

We have said that the average number of comparisons need to find a target value in an n-element list using sequential search is

bija089 [108]

Answer:

Part a: If the list contains n elements (where n is odd) the middle term is at index (n-1)/2 and the number of comparisons are (n+1)/2.

Part b: If the list contains n elements (where n is even) the middle terms are at index (n-2)/2 & n/2 and the number of comparisons are (n+2)/2.

Part c: The average number of comparisons for a list bearing n elements is 2n+3/4 comparisons.

Explanation:

Suppose the list is such that the starting index is 0.

Part a

If list has 15 elements, the middle item would be given at 7th index i.e.

there are 7 indices(0,1,2,3,4,5,6) below it and 7 indices(8,9,10,11,12,13,14) above it. It will have to run 8 comparisons to find the middle term.

If list has 17 elements, the middle item would be given at 8th index i.e.

there are 8 indices(0,1,2,3,4,5,6,7) below it and 8 indices(9,10,11,12,13,14,15,16) above it.It will have to run 9 comparisons to find the middle term.

If list has 21 elements, the middle item would be given at 10th index i.e.

there are 10 indices (0,1,2,3,4,5,6,7,8,9) below it and 10 indices (11,12,13,14,15,16,17,18,19,20) above it.It will have to run 11 comparisons to find the middle term.

Now this indicates that if the list contains n elements (where n is odd) the middle term is at index (n-1)/2 and the number of comparisons are (n+1)/2.

Part b

If list has 16 elements, there are two middle terms as one at would be at 7th index and the one at 8th index .There are 7 indices(0,1,2,3,4,5,6) below it and 7 indices(9,10,11,12,13,14,15) above it. It will have to run 9 comparisons to find the middle terms.

If list has 18 elements, there are two middle terms as one at would be at 8th index and the one at 9th index .There are 8 indices(0,1,2,3,4,5,6,7) below it and 8 indices(10,11,12,13,14,15,16,17) above it. It will have to run 10 comparisons to find the middle terms.

If list has 20 elements, there are two middle terms as one at would be at 9th index and the one at 10th index .There are 9 indices(0,1,2,3,4,5,6,7,8) below it and 9 indices(11,12,13,14,15,16,17,18,19) above it. It will have to run 11 comparisons to find the middle terms.

Now this indicates that if the list contains n elements (where n is even) the middle terms are at index (n-2)/2 & n/2 and the number of comparisons are (n+2)/2.

Part c

So the average number of comparisons is given as

((n+1)/2+(n+2)/2)/2=(2n+3)/4

So the average number of comparisons for a list bearing n elements is 2n+3/4 comparisons.

6 0

3 years ago

Unscramble thr words 1.Nsieg Wiev2.Seeathdat ievw​

Unscramble thr words 1.Nsieg Wiev2.Seeathdat ievw