3x² + 5x - 2 = 0
3x² + 6x - x - 2 = 0
3x(x) + 3x(2) - 1(x) - 1(2) = 0
3x(x + 2) - 1(x + 2) = 0
(3x - 1)(x + 2) = 0
3x - 1 = 0 or x + 2 = 0
+ 1 + 1 - 2 - 2
3x = 1 or x = -2
3 3 1 1
x = ¹/₃ or x = -2
f(x) = 3x² + 5x - 2
f(¹/₃) = 3(¹/₃)² + 5(¹/₃) - 2
f(¹/₃) = 3(¹/₉) + 1²/₃ - 2
f(¹/₃) = ¹/₃ - ¹/₃
f(¹/₃) = 0
(x, f(x)) = (¹/₃, 0)
f(x) = 3x² + 5x - 2
f(-2) = 3(-2)² + 5(-2) - 2
f(-2) = 3(4) - 10 - 2
f(-2) = 12 - 12
f(-2) = 0
(x, f(x)) = (-2, 0)
Vertical Asymptotes: ¹/₃ or -2
Horizontal Asymptotes: 0
Oblique Asymptote: No Asymptotes
Answer:
4x-6=4+4y+8=2
Step-by-step explanation:
Greater than 1 because left side is a fraction less than 1 and right side is a number greater than 1.
The left side being a fraction less than 1 could only mean that you have to multiply a number greater than 1 to the other side. And since the other side is a number greater already than 1 then multiplying the left side to the right side must result in a number greater than 1.
The lengths of the sides of the triangle are 8, 8, 20
Explanation:
Given that the perimeter of an isosceles triangle is 36 inches.
The base of the triangle is 
times longer than each of its legs.
We need to determine the lengths of the sides of the triangle.
<u>Lengths of the sides:</u>
Let x denote the lengths of the sides of the triangle.
The base of the triangle is given by
Perimeter of the isosceles triangle = Sum of the three sides of the triangle.
Thus, we have,
Thus, the length of the sides of the isosceles triangle is 8 inches.
Base of the triangle = 
Hence, the three sides of the isosceles triangle are 8, 8, 20
Answer:
The answer to your question is below
Step-by-step explanation:
Each square values two units
I hope it helps you.
