Given that,
y varies directly with x and y = 10 when x = 20.
To find,
The value of y when x = 15.
Solution,

Put x = 20 and y = 10

Put k = 1/2 and x = 15 to find the value of y.

So, the value of y is 7.5
Answer: Hence Pair( x, y) = [ 105/2, 105/2]
Step-by-step explanation:
Given that;
Among all pairs of numbers with a sum of 105;
the pair whose product is maximum = ?
so let pairs of numbers with a sum of 105 be x and y respectively
x + y = 105
let y = 105 - x
now
product = xy = x( 105 - x ) = 105x - x²
now
p(x) = 105x - x²
for maximum value of p
dp/dx =0
⇒ dp/dx = 105 - 2x = 0
2x = 105
x = 105/2
y + x = 105
y = 105 - x
y = 105 - 105/2 = 105/2
Hence Pair( x, y) = [ 105/2, 105/2]
Let b be the initial amount of books. Steve sells half of his books, so the number of Steve's books become

Then, he buys 6 more, so the number increases by 6:

This number is now 14, so you have

Subtract 6 from both sides:

Multiply both sides by 2:

<span>This really works well with wax paper. It is transparent and it leaves a visible white line on the crease. For the perpendicular bisector of a line segment, fold the endpoints of the line segment onto each other. The crease is the perpendicular bisector. This of course also gives you the midpoint, because that is where the perpendicular bisector intersects the line segment. For an angle bisector, put the crease through the vertex of the angle and lay the sides of the angle over top of each other. The crease is the angle bisecto
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Step-by-step explanation:
÷6
First, simplify the 6
to an improper fraction, which is:

Next rewrite the equation using the improper fraction:
÷
Now, in order to divide the fraction, we will need to flip the second fraction over, and then multiply the two fractions together. A great way to remember this is the phrase <em>Copy Dot Flip - </em>Copy the first fraction, put a dot for multiplication, and flip the second fraction.
·
Finally, multiply together and simplify/reduce if needed:
<u>The final answer is </u>
<u> and no simplification or reduction is needed</u>