If
z^3=-64
then:
z=(-64)^(1/3)
z=-4
Answer:
The only function that has only one zero at -6 is f(x) = (x + 6)(x + 6)
Step-by-step explanation:
We have a function:
f(x)=(x+6)(x+6)
This function is also equal to f(x)=(x+6)^2
This is the square of the binomial. It has only one zero
f(x)=(x+6)^2 = 0
If we take square root we get:
√(x+6)^2 = 0
x+6 =0
x= -6
The only function that has only one zero at -6 is f(x) = (x + 6)(x + 6)....
The answer is 3x2+8x+9 I had the question before
