The angle m∠AFE is 128 degrees.
<h3>How to find angles?</h3>
∠AFB ≅ ∠EFD
∠EFD = 5x + 6
m∠DFC = (19x - 15)°
m∠EFC = (17x + 19)°
m∠AFE = ?
m∠AFB + m ∠EFD + m∠AFE = 180
Therefore,
5x + 6 + 5x + 6 + m∠AFE = 180
5x + 5x + 6 + 6 + m∠AFE = 180
10x + 12 + m∠AFE = 180
10x + m∠AFE = 180 - 12
10x + m∠AFE = 168
m∠AFE = 168 - 10x
m∠EFC = m ∠EFD + m∠DFC
17x + 19 = 5x + 6 + 19x - 15
17x - 5x - 19x = 6 - 15 - 19
-7x = - 28
x = 28 / 7
x = 4
Therefore,
m∠AFE = 168 - 10x
m∠AFE = 168 - 10(4)
m∠AFE = 168 - 40
m∠AFE = 128°
Therefore, the angle m∠AFE = 128°
learn more on angles here: brainly.com/question/13212279
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Answer:
Tash scores 40 baskets
Step-by-step explanation:
Rani = R
Layla = L
Tash = T
R = 4L
T = 4L-8
As L + R + T = 100
L + 4L + 4L-8 = 100
Collect like terms
9L - 8 = 100
+ 8 both sides
9L = 108
divide by 9 both sides
L = 108 / 9
L = 12
Now..... T = 4L-8 substitute L with 12
T = 48 - 8
T = 40
2 2/3 is an answer, your welcome
(x+y)0
(-3+5)0
(-15)0
THE ANSWER IS 0 BECAUSE YOU ARE MULTIPLYING BY 0
Answer:
Step-by-step explanation:
The max value that this function reaches is 6, and the function reaches this value repeatedly, beginning at x = 0 and then at x = 6, 12, 15, etc. This tells us that the period of the function is 6.
The function is increasing on (3, 6), (9, 12), and so on
The function is even because the graph is symmetrical about the y-axis.
