Answer:
m= -3/2
Step-by-step explanation:
First, we must find the slope of the line given. We are given the equation:
y-2/3x=2
We must get this equation in slope-intercept form: y=mx+b (where m is the slope and b is the y-intercept). In order to do this, we must get y isolated.
2/3x is being subtracted from y. We want to preform the inverse, so we should add 2/3x to both sides.
y-2/3x+2/3x=2+2/3x
y=2+2/3x
Rearrange the terms.
y= 2/3x+2
Now the equation is in slope intercept form. (y=mx+b). 2/3 and x are being multiplied, so we know that the slope is 2/3.
Now, we have to find the perpendicular slope. Perpendicular lines have negative reciprocal slopes.
1. Negative
m=2/3
Negate the slope.
m= -2/3
2. Reciprocal
m= -2/3
Flip the numerator (top number) and denominator (bottom number).
m= -3/2
The perpendicular slope is -3/2
Answer:
is a subset of 
Step-by-step explanation:
Required
Difference between subset and proper subset
To answer this question, I will use the following illustration.
In the above sets, set B is a proper subset of set A because all elements of B can be found in A, but not element of A can be found in B.
Set C is a subset of A because 
Using the above illustration, we have:
and
is a subset of , because 5 and 8 are in but 2 which ca be found in is not in
36×0.25=9 and 9÷3=6. So 6 apples are left after making these desserts.
Answer:
Step-by-step explanation:
50% = 0.5
(5 * 5) + (0.5 * 2) =
25 + 1 =
26 <===
Split up the interval [0, 2] into <em>n</em> equally spaced subintervals:
![\left[0,\dfrac2n\right],\left[\dfrac2n,\dfrac4n\right],\left[\dfrac4n,\dfrac6n\right],\ldots,\left[\dfrac{2(n-1)}n,2\right]](https://tex.z-dn.net/?f=%5Cleft%5B0%2C%5Cdfrac2n%5Cright%5D%2C%5Cleft%5B%5Cdfrac2n%2C%5Cdfrac4n%5Cright%5D%2C%5Cleft%5B%5Cdfrac4n%2C%5Cdfrac6n%5Cright%5D%2C%5Cldots%2C%5Cleft%5B%5Cdfrac%7B2%28n-1%29%7Dn%2C2%5Cright%5D)
Let's use the right endpoints as our sampling points; they are given by the arithmetic sequence,
where 
. Each interval has length 
.
At these sampling points, the function takes on values of
We approximate the integral with the Riemann sum:
Recall that
so that the sum reduces to
Take the limit as <em>n</em> approaches infinity, and the Riemann sum converges to the value of the integral:
Just to check:
