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3 years ago

Use distributive property to rewrite the expression 3x(x+4)

Mathematics

1 answer:

Ugo [173]3 years ago

6 0

Answer:

3x^2 + 12x

Step-by-step explanation:

3x(x +4)

3x^2 + 12x

- Multiply 3x * x = 3x^2

- Multiply 3x * 4 = 12x

Which Gives You 3x^2 + 12x

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Please Graph 4x + 6y = 12 step by step

aniked [119]

$4x+6y=12\\6y=-4x+12\\\\y=-\frac{4}{6}x+2\\\\y=-\frac{2}{3}x+2\\\\x-intercept\ (y=0):\\-\frac{2}{3}x+2=0\\-\frac{2}{3}x=-2\\x=(-2)\times(-\frac{3}{2})\\x=3\to(3;\ 0)\\\\y-intrcept\ (x=0)\\y=-\frac{2}{3}\times0+2=2\to(0;\ 2)\\\\look\ at\ the\ picture$ Answer here

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3 years ago

The toll to a bridge is 2.50. A three-month pass costs $12.00 and reduces the toll to $0.50. A six month pass $37 and permits cr

Gnoma [55]

c=number of crossings; Q=quarterly pass; S=semi-annual pass; P=pay as you go

P=$2.50c

Q=$12+$0.50c

S=$40

Compare single pay and quarterly ticket:

$2.50c=$12+$0.50c Subtract $0.50c from each side

$2.00c=$12 Divide each side by $2.

c=6 6 crossings is the break even for single pay and quarterly ticket: more crossings favor the ticket.

Compare quarterly and semi-annual tickets:

3 month pro-rated cost of semi annual ticket=$20

$20=$12+$0.50c Subtract 12 from each side

$8=$0.50c Divide each side by $0.50

16=c The break=even point between quarterly and semi annual tickets is 16 crossings per 3 months. More than this favors the semi annual ticket.

ANSWER: The three month pass is the best deal if you cross between 6 and 16 times during the three month period.

I hope this help you

8 0

3 years ago

1.) Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth .x squared minus 21 x equals n

Andrew [12]

Part 1
We are given $x^2-21x=-4x$ . This can be rewritten as $x^2-18x=0$ .
Therefore, a=1, b=-18, c=0.
Using the quadratic formula
$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-\left(-18\right)\pm \sqrt{\left(-18\right)^2-4\left(1\right)\left(0\right)}}{2\left(1\right)}$
$x=\frac{18\pm 18}{2}$

The values of x are
$x_1=\frac{18-18}{2}=0$
$x_2=\frac{18+18}{2}=18$

Part 2
Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a quadratic function.

Part 3.
The first equation is $y=x^2+2$ .
The second equation is $y=3x+20$ .

We have
$x^2+2=3x+20$
$x^2-3x-18=0$
Factoring, we have
$\left(x-6\right)\left(x+3\right)=0$
Equating both factors to zero.
$x_1-6=0\rightarrow x_1=6$
$x_2+3=0\rightarrow x_2=-3$

When the value of x is 6, the value of y is
$y=3\left(6\right)+20=38$

When the value of x is -3, the value of y is
$y=3\left(-3\right)+20=11$

Therefore, the solutions are (6,38) or (-3,11)

7 0

3 years ago

A rectangle has an area of 364.5 cm2. If its length is 27 cm, find its<br> perimeter.

dimulka [17.4K]

Wiskksjkxkc jefe jifvnjcrg morboso

4 0

3 years ago

I am confused on this is it 1/8

Oxana [17]

Yes it is 1/8.You don’t multiply the top part of the fraction,just the bottom.

6 0

4 years ago

Use distributive property to rewrite the expression 3x(x+4)​

Use distributive property to rewrite the expression 3x(x+4)