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Arturiano [62]
3 years ago
9

*Urgent* im not sure look at the picture

Mathematics
2 answers:
andreev551 [17]3 years ago
8 0
It’s would be letter B 43.4 miles
Dmitrij [34]3 years ago
3 0

Answer:

43.4 mph

Step-by-step explanation:

super simple, you can disregard all the speed stuff, since they are both hours, it is useless information. all you have to do is convert distances, so multiply 70 by .62 to get 43.4milers per hour.

if you have any questions, leave them in the comments, i will try to answer them, pls give brainliest if this helps.

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Bradley completed 3/5 of his homework. What percent of his homework does he still need to complete?
muminat
3/5 = 6/10 (which is 60%) 100% - 60% = 40%
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A bar graphs shows that sports books received 9 votes. If the scale is 0 to 20 by twos , where should the bar end for the sports
olya-2409 [2.1K]
A little past the 8.
7 0
3 years ago
How do you solve his with working
AlexFokin [52]
Check the picture below.

a)

so the perimeter will include "part" of the circumference of the green circle, and it will include "part" of the red encircled section, plus the endpoints where the pathway ends.

the endpoints, are just 2 meters long, as you can see 2+15+2 is 19, or the radius of the "outer radius".

let's find the circumference of the green circle, and then subtract the arc of that sector that's not part of the perimeter.

and then let's get the circumference of the red encircled section, and also subtract the arc of that sector, and then we add the endpoints and that's the perimeter.

\bf \begin{array}{cllll}
\textit{circumference of a circle}\\\\ 
2\pi r
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{arc's length}\\\\
s=\cfrac{\theta r\pi }{180}
\end{array}\\\\
-------------------------------

\bf \stackrel{\stackrel{green~circle}{perimeter}}{2\pi(7.5) }~-~\stackrel{\stackrel{green~circle}{arc}}{\cfrac{(135)(7.5)\pi }{180}}~+
\stackrel{\stackrel{red~section}{perimeter}}{2\pi(9.5) }~-~\stackrel{\stackrel{red~section}{arc}}{\cfrac{(135)(9.5)\pi }{180}}+\stackrel{endpoints}{2+2}
\\\\\\
15\pi -\cfrac{45\pi }{8}+19\pi -\cfrac{57\pi }{8}+4\implies \cfrac{85\pi }{4}+4\quad \approx \quad 70.7588438888



b)

we do about the same here as well, we get the full area of the red encircled area, and then subtract the sector with 135°, and then subtract the sector of the green circle that is 360° - 135°, or 225°, the part that wasn't included in the previous subtraction.


\bf \begin{array}{cllll}
\textit{area of a circle}\\\\ 
\pi r^2
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{area of a sector of a circle}\\\\
s=\cfrac{\theta r^2\pi }{360}
\end{array}\\\\
-------------------------------

\bf \stackrel{\stackrel{red~section}{area}}{\pi(9.5^2) }~-~\stackrel{\stackrel{red~section}{sector}}{\cfrac{(135)(9.5^2)\pi }{360}}-\stackrel{\stackrel{green~circle}{sector}}{\cfrac{(225)(7.5^2)\pi }{360}}
\\\\\\
90.25\pi -\cfrac{1083\pi }{32}-\cfrac{1125\pi }{32}\implies \cfrac{85\pi }{4}\quad \approx\quad 66.75884

7 0
3 years ago
A fitness center currently has 320 members. Monthly membership fees are $45. The manager of the fitness center has determined th
murzikaleks [220]

Are we subtracting the total or ? What's the question. , If so that would be 310 members as of the $5 raise in fees

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Help asap
ehidna [41]
Angles A and B are exactly the same because
they are congruent angles

Hope This Helps!!!!!
4 0
3 years ago
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