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tamaranim1 [39]
2 years ago
13

Find x. Give your answer in the

Mathematics
1 answer:
ASHA 777 [7]2 years ago
5 0

Answer:

Es in simplo deviso con lado

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How do you integrate arctan(x dx? i think that if you simplify the integral you get:?
Temka [501]
Integration by parts will help here. Letting u=\arctan x and \mathrm dv=\mathrm dx, you end up with \mathrm du=\dfrac{\mathrm dx}{1+x^2} and v=x. Now

\displaystyle\int\arctan x\,\mathrm dx=uv-\int v\,\mathrm du
\displaystyle\int\arctan x\,\mathrm dx=x\arctan x-\int\frac x{1+x^2}\,\mathrm dx

For the remaining integral, setting y=1+x^2 gives \dfrac{\mathrm dy}2=x\,\mathrm dx, so

\displaystyle\int\frac x{1+x^2}\,\mathrm dx=\frac12\int\frac{\mathrm dy}y=\frac12\ln|y|+C=\frac12\ln(1+x^2)+C

Putting everything together, you end up with

\displaystyle\int\arctan x\,\mathrm dx=x\arctan x-\frac12\ln(1+x^2)+C
6 0
3 years ago
F4f <br> fendimulatto <br> juicyminkz
lapo4ka [179]

Answer:

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Step-by-step explanation:

<h2>Nice</h2>
7 0
3 years ago
What is the inverse function of d(x) = 2x - 4?
zysi [14]

Answer:

d^{-1}(x) = \frac{x+4}{2}

Step-by-step explanation:

let d(x) = y and rearrange making x the subject, that is

2x - 4 = y ( add 4 to both sides )

2x = y + 4 ( divide both sides by 2 )

x = \frac{y+4}{2}

Change y back into terms of x, so

d^{-1}(x ) = \frac{x+4}{2}

7 0
3 years ago
In circle A as shown below, segment DC is tangent to circle A at D.
Likurg_2 [28]

Answer:

AB = 3

Step-by-step explanation:

AB = AD

AB² + 4² = (AB + 2)²

AB² + 16 = AB² + 4AB + 4

combine like terms:

4AB = 12

AB = 3

4 0
3 years ago
Read 2 more answers
HELP ASAP<br><br> Write the equation of the line passing through the points (-5,8) and (-8,5).
ycow [4]

Answer:

y=-5/8x+0

Step-by-step explanation:

8 0
3 years ago
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