The major dissolved constituents of ocean water, such as sodium and chloride ions, are __________ properties of seawater.

Chemistry

1 answer:

Darya [45]4 years ago

5 0

Answer:

Conservative Properties of Seawater

Explanation:

The Conservative properties of seawater refer to those properties that cannot be altered due to the occurrence of physical, chemical and biological processes, over the large oceanic bodies. This typically comprises properties such as the temperature and also there is a high concentration of both sodium and chloride ions, which increases the salinity of the oceans.

These conservative properties occur in almost a fixed amount, or it most probably changes at a very slower rate through time. They can be considered to have a long residence time.

You might be interested in

How many grams of P4O10 (292.88 g/mol) form when phelpsphorous (P4, 125.52 g/mol) reacts with 16.2 L of O2 (33.472 g/mol) ) at s

nevsk [136]

Answer:

40.5 g of P₄O₁₀ are produced

Explanation:

We state the reaction:

P₄ + 5O₂ → P₄O₁₀

We do not have data from P₄ so we assume, it's the excess reactant.

We need to determine mass of oxygen and we only have volumne so we need to apply density.

Density = mass / volume, so Mass = density . volume

Denstiy of oxygen at STP is: 1.429 g/L

1.429 g/L . 16.2L = 23.15 g

We determine the moles: 23.15 g . 1mol / 33.472g = 0.692 moles

5 moles of O₂ can produce 1 mol of P₄O₁₀

Our 0.692 moles may produce (0.692 . 1)/ 5 = 0.138 moles

We determine the mass of product:

0.138 mol . 292.88 g/mol = 40.5 g

3 0

3 years ago

How many grams are in 4.63 ×1024 molecules of CCl4

Lynna [10]

Answer:

m =1,182.8g

Explanation:

there you go

4 0

2 years ago

A student carried out a simple distillation on a compound known to boil at 124 oc and they reported a boiling point of 116-117 o

chubhunter [2.5K]

Answer :

The correct answer is due to incorrect position of thermometer .

Distillation is process of separating two volatile liquids on the basis of their boiling points .In involves the following set up ( shown in image )

Since the Boiling point is found is 116-117 C which is near to 124 C , also the purity was checked and thermometer was calibrated .

So the only error could be possible is position of thermometer .

The position of bulb of thermometer is very important to get an accurate reading of boiling point .The vapor so formed should touch the side walls of bulb as soon as they are formed .

May be the bulb of thermometer was kept far from the vapors formed by liquid so, s<u>ome of the vapor before reaching to bulb start condensing and their Temperature decreases </u>.

Hence , the temperature shown by thermometer was decrease than actual boiling point due to incorrect position of thermometer.