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Mazyrski [523]
3 years ago
8

9. How many moles of H2SO4 are there in 98 g of H2so4

Chemistry
1 answer:
Maksim231197 [3]3 years ago
6 0

Hey there!:

molar mass H₂SO₄ => 98.079 g/mol

Therefore :

number of moles  = mass of solute / molar mass

number of moles = 98 / 98.079

number of moles = 0.0009991 moles

Hops this helps!

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Kay [80]

Answer:

Explanation:

H3PO4.

7 0
3 years ago
Read 2 more answers
We wish to dilute some 18.4 m h2so4 solution to make 600 ml of a 0.1 m h2so4 solution. how much of the 18.4 m solution should we
Aleks [24]
We can use the following formula when making diluted solutions from concentrated solutions
c1v1 = c2v2
where c1 is concentration and v1 is volume of the concentrated solution 
and c2 is concentration and v2 is final volume of diluted solution 
substituting the values in the equation
18.4 M x V = 0.1 M x 600 mL 
V = 3.26 mL
volume of 3.26 mL of 18.4 M sulfuric acid solution should be taken and diluted upto 600 mL
3 0
4 years ago
In ΔDEF, the measure of ∠F=90°, FE = 16, DF = 63, and ED = 65. What ratio represents the tangent of ∠E?
amid [387]

Answer:

63/16

Explanation:

tanE=  

adjacent

opposite

​  

=  

16

63

​

5 0
4 years ago
Heterogeneous mixture containing a liquid in which visible particles settle
suter [353]
A suspension is the answer
7 0
4 years ago
A 51.9 g sample of quartz is put into a calorimeter (see sketch at right) that contains 300.0 g of water. The quartz sample star
Trava [24]

Answer:

The specific heat capacity of quartz is 0.71 J/g°C.

Explanation:

Heat lost by quartz will be equal to heat gained by the water

-Q_1=Q_2

Mass of quartz= m_1=51.9 g

Specific heat capacity of quartz= c_1=?

Initial temperature of the quartz= T_1=97.8^oC

Final temperature = T_2=T  = 19.3^oC

Q_1=m_1c_1\times (T-T_1)

Mass of water=m_2=300.0 g

Specific heat capacity of water= c_2=4.18 J/g^oC

Initial temperature of the water = T_3=17.0 ^oC

Final temperature of water = T_2=T=19.3^oC

Q_2=m_2c_2\times (T-T_3)

-Q_1=Q_2

-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)

On substituting all values:

-(51.9 gc_1\times (19.3^oC-97.8^oC))=300.0 g\times 4.18 J/g^oC\times (19.3^oC-170^oC)

we get:

c_1 =0.7079 J/g^oC\approx 0.71 J/g^oC

The specific heat capacity of quartz is 0.71 J/g°C.

5 0
3 years ago
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