I think that it is attempt. If i am wrong, sorry.
Answer:
z = 11
Explanation:
5y + 13 = 6y
Subtract 5y by both sides.
13 = y
Next,
z + 22 = 3z
Subtract z by both sides.
22 = 2z
Then, divide both sides by 2.
11 = z
Finally plug those answers into the equations.
5(13) + 13 = 78
6(13) = 78
(11) + 22 = 33
3(11) = 33
So △DEF ≅ △JKI because the value of z = 11.
The sequence is arithmetic since the common difference that is equal
d=11-15=7-11=-4
a(n) = a1 +(n-1)d
a1=15
=
a(n) = 15+(n-1)-4
To compare the two classes, the Coefficient of Variation (COV) can be used.
The formula for COV is this:
C = s / x
where s is the standard deviation and x is the mean
For the first class:
C1 = 10.2 / 75.5
C1 = 0.1351 (13.51%)
For the second class:
C2 = 22.5 / 75.5
C2 = 0.2980 (29.80%)
The COV is a test of homogeneity. Looking at the values, the first class has more students having a grade closer to the average than the second class.