How to trap a private number
2 answers:
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Answer:
Following are the code to this question:
file= open('book.txt') #open file
li= {} #define an empty list
for lines in file: # use for loop Split file data into words
d= lines.lower().strip(' !?').split() #define variable d that Add it to map
for val in d: #define loop to store data
if val not in li: #check value is not in list
li[val] = 0 #define list and assign value in 0
li[val] = li[val] + 1 #Sort the book data and add its value
m = sorted(li.items(),key = lambda x : -x[1]) #sorted value into the m variable
print(m[:10]) #print value
Output:
please find the attachment.
Explanation:
In the given python code first, we open the file "book.txt", in next line, an empty list is defined, that uses the for loop which can be described as follows:
- In the for loop is used, that reads the file data, and defines a variable "d", that stores the values into the map.
- In the next line another loop is used, that check file values, if values are the same type so, it adds values and writes it.
- In the last line, m variable is used, that sorts the values and use the slicing to print its value.
