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2 years ago

the area of the triangle below is 1/4 square meters. what is the length of the base. express your answer in simplest form

Mathematics

1 answer:

Alexeev081 [22]2 years ago

5 0

Answer:

4/5

Step-by-step explanation:

Given,

Area of the triangle = 1/4 square meters

From the diagram,

Height = 2/5 m

To find : Length of the base

Formula : -

A = bh/2

Here,

A denotes Area

b denotes Base

h denotes Height

A = 1/4

h = 2/5

A = bh/2

Cross multiply,

A * 2 = bh

2A = bh

2 * (1/4) = b * (2/5)

(1 * 2)/4 = (b * 2)/5

2/4 = 2b/5

1/2 = 2b/5

Cross multiply,

1 * 5 = 2 * 2b

5 = 4b

b = 4/5 meters

Hence,

The length of the base is 4/5 meters.

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when measuring ,100degrees Fahrenheit squat to 37.7777 degrees celsius. Round to the nearest thousandth

Gre4nikov [31]

Answer: 37.778 degrees

Step-by-step explanation:

The third digit to the right of the decimal is thousandths. If the next digit to the right of that is 5 or more, add one to the thousandths. Otherwise leave it as is. Just drop everything to the right of the place you rounded to.

7 is greater than 5, so add 1 to the 7 in the thousandths place and get

37.778

8 0

3 years ago

If f(x) = x + 1, and g(x) = 2x the g(f(x)) =

Slav-nsk [51]

2(x+1)
2x+2 is your final answer

3 0

3 years ago

9/20

NISA [10]

For this case we must find the solution of the following quadratic equation:

$x ^ 2 + 5x + 7 = 0$

Where:

$a = 1\\b = 5\\c = 7$

Then, the solution is given by:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

Substituting the values:

$x = \frac {-5 \pm \sqrt {5 ^ 2-4 (1) (7)}} {2 (1)}\\x = \frac {-5 \pm \sqrt {25-28}} {2}\\x = \frac {-5 \pm \sqrt {-3}} {2}$

By definition we have: $i ^ 2 = -1$

$x = \frac {-5 \pm \sqrt {3i ^ 2}} {2}\\x = \frac {-5 \pm i \sqrt {3}} {2}$

Thus, we have two complex roots.

Answer:

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4 0

4 years ago

Use the distance formula to calculate the length of the leg CD

Karo-lina-s [1.5K]

To calculate the distance between two points on the coordinate system you have to use the following formula:

$d=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2}$

Where

d represents the distance between both points.

(x₁,y₁) are the coordinates of one of the points.

(x₂,y₂) are the coordinates of the second point.

To determine the length of CD, the first step is to determine the coordinates of both endpoints from the graph

C(2,-1)

D(-1,-2)

Replace the coordinates on the formula using C(2,-1) as (x₁,y₁) and D(-1,-2) as (x₂,y₂)

$\begin{gathered} d_{CD}=\sqrt[]{(2-(-1))^2+((-1)-(-2))}^2 \\ d_{CD}=\sqrt[]{(2+1)^2+(-1+2)^2} \\ d_{CD}=\sqrt[]{3^2+1^2} \\ d_{CD}=\sqrt[]{9+1} \\ d_{CD}=\sqrt[]{10} \end{gathered}$

The length of CD is √10 units ≈ 3.16 units

6 0

1 year ago

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Westkost [7]

I think it's 10^-7 hope that helps

7 0

3 years ago

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