I think is oxygen that what i think
Complete Question
Determine the end (final) value of n in a hydrogen atom transition, if the electron starts in n=4 and the atom emits a photon of light with a wavelength of 486 nm. Group of answer choices
Answer:
Explanation:
From the question we are told that:
Wavelength 
Generally the equation for Atom Transition is mathematically given by
Where
Rydberg constant 
Therefore
Answer:
False hypermagnesaemia
Explanation:
Magnesium is predominantly an intracellular divalent action and it is important for optimal cellular function. It is an essential cofactor to many enzymes as well as being important for membrane function.
The body contain about 1 mol (approximately 25g) of magnesium.
Hemolyzed specimen will result in release of magnesium from intracellular to extracellular, causing elevation of the blood level of magnesium. This is a false hypermagnesaemia because it doesn't represent the real blood level.
According to the balanced equation of this reaction:
N2(g) + 3H2(g) ↔ 2NH3(g)
and when we have Kp = 4.51 x 10^-5 so, in the Kp equation we will substitute by the value of the P for each gas to compare the value with Kp = 4.51x10^-5
a) when we have 98 atm NH3, 45 atm N2, 55 atm H2 by substitution in Kp equation:
Kp= [p(NH3)]^2 / [p(N2)]*[p(H2)]^3 = [98]^2 / [45]*[55]^3
= 1.28x10^-3
So here the value is higher than the value of the given Kp.
so the reaction will go leftwards toward the reactants ( to reduce the value of Kp) to reach the equilibrium.
b) When 57 atm NH3, 143 atm N2, No H2 so like a) by substitution:
Kp = [57]^2 / [143] = 22.7
So the reaction will go leftwards toward the reactants to reduce the value of Kp to reach equilibrium.
c) when 13 atm NH3, 27 atm N2, 82 H2
Kp = [13]^2 / [27]*[82]^3 = 1.135 x 10^-5 So this value is lower than the Kp which is given.
so, the reaction will go towards the right toward the products to increase the value of Kp to reach the equilibrium.
