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sp2606 [1]
3 years ago
5

A blood specimen is collected in a heparin-containing tube for calcium and magnesium determination. Upon centrifugation, the pla

sma appeared hemolyzed. How would this affect the magnesium value?
Chemistry
1 answer:
Firdavs [7]3 years ago
3 0

Answer:

False hypermagnesaemia

Explanation:

Magnesium is predominantly an intracellular divalent action and it is important for optimal cellular function. It is an essential cofactor to many enzymes as well as being important for membrane function.

The body contain about 1 mol (approximately 25g) of magnesium.

Hemolyzed specimen will result in release of magnesium from intracellular to extracellular, causing elevation of the blood level of magnesium. This is a false hypermagnesaemia because it doesn't represent the real blood level.

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Near water, change in elevation, or change in latitude.

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How many atoms are in 15.0 moles of C2H6O
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1 mole = 6.22 x 10^23 molecules (Avogadro's number)
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3 0
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which types of intermolecular forces are most likely to dominate between large molecules containing long chains of carbon atoms
Serga [27]

Van der waals force

Explanation:

The intermoleclular forces are attraction between molecules. Interatomic forces are attraction between atoms in a compound.

In most hydrocarbons the weak Van der waals attraction are known.

  • These forces are weak attraction joining non-polar and polar molecules together.
  • These forces can also be found in layers of graphite.
  • They are of two types;

London dispersion forces are attraction that exists between non-polar molecules and the noble gas.

Dipole - Dipole attractions are forces of attraction existing in polar molecules.

In hydrocarbons, we have non-polar molecules and intermolecular attraction is london dispersion forces.

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Intermolecular forces brainly.com/question/10107765

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6 0
3 years ago
Suggest why it might be difficult and dangerous to test sodium for electrical conductivity?​
lukranit [14]

Answer:

It might cause fire or extreme smoke.

Explanation:

8 0
2 years ago
How many grams of solid NaOH are required to prepare a 400ml of a 5N solution? show your work!
Nuetrik [128]

<u>Answer:</u> The mass of solid NaOH required is 80 g

<u>Explanation:</u>

Equivalent weight is calculated by dividing the molecular weight by n factor. The equation used is:

\text{Equivalent weight}=\frac{\text{Molecular weight}}{n}

where,

n = acidity for bases = 1 (For NaOH)

Molar mass of NaOH = 40 g/mol

Putting values in above equation, we get:

\text{Equivalent weight}=\frac{40g/mol}{1eq/mol}=40g/eq

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.

Mathematically,

\text{Normality of solution}=\frac{\text{Number of gram equivalents} \times 1000}{\text{Volume of solution (in mL)}}

Or,

\text{Normality of solution}=\frac{\text{Given mass}\times 1000}{\text{Equivalent mass}\times \text{Volume of solution (in mL)}}         ......(1)

We are given:

Given mass of NaOH = ?

Equivalent mass of NaOH = 40 g/eq

Volume of solution = 400 mL

Normality of solution = 5 eq/L

Putting values in equation 1, we get:

5eq/L=\frac{\text{Mass of NaOH}\times 1000}{40g/eq\times 400mL}\\\\\text{Mass of NaOH}=80g

Hence, the mass of solid NaOH required is 80 g

4 0
3 years ago
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