<span>Answer: 100 ml
</span>
<span>Explanation:
1) Convert 1.38 g of Fe₂S₃ into number of moles, n
</span>i) Formula: n = mass in grass / molar mass
<span>
ii) molar mass of </span><span>Fe₂S₃ =2 x 55.8 g/mol + 3 x 32.1 g/mol = 207.9 g/mol
</span>
iii) n = 1.38 g / 207.9 g/mol = 0.00664 moles of <span>Fe₂S₃
</span>
<span>2) Use the percent yield to calculate the theoretical amount:
</span>
<span>65% = 0.65 = actual yield/ theoretical yield =>
</span>theoretical yield = actual yield / 0.65 = 0.00664 moles / 0.65 = 0.010 mol <span>Fe₂S₃</span><span>
3) Chemical equation:
</span>
<span> 3 Na₂S(aq) + 2 FeCl₃(aq) → Fe₂S₃(s) + 6 NaCl(aq)
4) Stoichiometrical mole ratios:
</span>
<span>3 mol Na₂S : 2 mol FeCl₃ : 1 mol Fe₂S₃ : 6 mol NaCl
5) Proportionality:
</span>2moles FeCl₃ / 1 mol Fe₂S₃ = x / 0.010 mol Fe₂S₃
<span>
=> x = 0.020 mol FeCl₃
6) convert 0.020 mol to volume
</span>
<span>i) Molarity formula: M = n / V
</span>
<span>ii) V = n / M = 0.020 mol / 0.2 M = 0.1 liter = 100 ml
</span>
Is there a graph? I need to see a graph in order to help
Answer:
1 is the correct answer:)
Subtract
3
33
from both sides of the equation
2+3=5
Simplify
Subtract
5
5x5x
from both sides of the equation
Simplify
Divide both sides of the equation by the same term
Simplify
than you will have 1.
Answer:
After 2000 years, the first after will be 4m lower.
After 2000 years, the second area will be 14m higher.
Explanation:
From the given information:
At the first area:
if the wind is eroding at 2 mm/year, then after 2000 years; we have:
2 mm/year × 2000 year = 4000 mm
4000 mm to meters, we have:
= 4 m lower
At the second smaller area:
Given that the wind is depositing it at the rate of 7 mm per year;
Then:
7 mm/year × 2000 year = 14000 mm
=14 m higher
