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Nataly_w [17]
2 years ago
8

On a coordinate plane, the points are (3, 1), (6, 2), (8, 3), (12, 4).

Mathematics
2 answers:
ArbitrLikvidat [17]2 years ago
5 0

Answer:

it would be 8 to 3

which is not equivalent

Step-by-step explanation:

the reason why is because of this

3, 6, 9, 12.

not:

3, 6, <em>8, </em>12.

ollegr [7]2 years ago
3 0

Answer: Yup hes correct

Have a great day!

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The equations of two functions are y=-21x+9 and y=24x+8 which function is changing more quickly? Explain
antoniya [11.8K]

Given:

The equations are

y=-21x+9

y=24x+8

To find:

Which function is changing more quickly.

Solution:

The slope intercept form of a line is

y=mx+b

Where m is slope and b is y-intercept.

On comparing y=-21x+9 with the slope intercept form, we get

m_1=-21

|m_1|=|-21|

|m_1|=21

On comparing y=24x+8 with the slope intercept form, we get

m_2=24

|m_2|=24

Since, |m_1|, it means the absolute rate of change of second function is greater than the first function.

Therefore, the second function is changing more quickly.

3 0
3 years ago
At the movie theatre, child admission is $6.40 and adult admission is $9.90. On Friday, 154 tickets were sold for a total sales
Minchanka [31]
6.40x+9.90(154-x)=1230.90
Solve for x
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3 years ago
WHAT IS THE DIFFERENCE BETWEEN RECURSIVE AND EXPLICIT FORMULAS FOR SEQUENCES AND SERIES'?
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3 years ago
Suppose that 70% of college women have been on a diet within the past 12 months. A sample survey interviews an SRS of 267 colleg
Fofino [41]

Answer:

The probability that 75% or more of the women in the sample have been on a diet is 0.037.

Step-by-step explanation:

Let <em>X</em> = number of college women on a diet.

The probability of a woman being on diet is, P (X) = <em>p</em> = 0.70.

The sample of women selected is, <em>n</em> = 267.

The random variable thus follows a Binomial distribution with parameters <em>n</em> = 267 and <em>p</em> = 0.70.

As the sample size is large (n > 30), according to the Central limit theorem the sampling distribution of sample proportions (\hat p) follows a Normal distribution.  

The mean of this distribution is:

\mu_{\hat p} = p = 0.70

The standard deviation of this distribution is: \sigma_{\hat p}=\sqrt{\frac{p(1-p}{n}} =\sqrt{\frac{0.70(1-0.70}{267}}=0.028

Compute the probability that 75% or more of the women in the sample have been on a diet as follows:

P(\hat p \geq 0.75)=P(\frac{\hat p-\mu_{\hat p}}{\sigma_{\hat p}} \geq \frac{0.75-0.70}{0.028}) =P(Z\geq0.179)=1-P(Z

**Use the <em>z</em>-table for the probability.

P(\hat p \geq 0.75)=1-P(Z

Thus, the probability that 75% or more of the women in the sample have been on a diet is 0.037.

7 0
3 years ago
Remy has a job at the local store. He spends $80 in a game parlor and $250 for food per month, and saves the rest of his salary.
Serga [27]
I think B would be the right answer
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3 years ago
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