A scale drawing of a school playground in the shape of a rectangle is shown. What is the area in square meters of the playground

Mathematics

1 answer:

Ilya [14]2 years ago

3 0

Answer:

Step-by-step explanation:

8×19= 152

1 : 4.5

152×4.5=684

You might be interested in

Please please please.

sesenic [268]

the possibilities are probably b, using the elimination method

4 0

2 years ago

Which function can be used to find the number of ounces of coffee in the can based on its radius?

8090 [49]

Answer:

Step-by-step explanation:

The answer is A I hope it helped!

5 0

3 years ago

In your opinion, which step includes a mistake:

Ilya [14]

Answer:

yes Cecilia make her first mistake in step 2

8 0

2 years ago

D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x

MA_775_DIABLO [31]

The solution depends on the value of $k$ . To make things simple, assume $k>0$ . The homogeneous part of the equation is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0$

and has characteristic equation

$r^2-16k=0\implies r=\pm4\sqrt k$

which admits the characteristic solution $y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}$ .

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be $y_p=ae^{4x}+be^x$ . Then

$\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x$

So you have

$16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x$
$(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x$

This means

$16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}$
$b(1-16k)=30\implies b=\dfrac{30}{1-16k}$

and so the general solution would be

$y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x$