Given: Triangle ABC with segment AD drawn from vertex A and intersecting side CB.
To Find: First Step towards proving the similarity of triangles ΔABC and ΔDBA.
Solution:
In ΔABC and ΔDBA
As we can see that to prove that two triangles are similar , their corresponding sides should be proportional and their corresponding interior angles should be equal.
As Ratio of corresponding sides of triangles ΔABC and ΔDBA are not given.
But we can observe from two triangles that
Angle B is common between two triangles ΔABC and ΔDBA , whatever be the measure of angle B .
So, Option (B): Angle B is congruent to itself is correct option.