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3 years ago

10

On a summer day, Thomas is standing in his driveway waiting for his mother. Energy from the Sun is making Thomas feel hot. This

energy is being transmitted by three different methods. Which of the following is an example of convection?

1 answer:

Leno4ka [110]3 years ago

4 0

Answer:

A. Energy streaming through space toward Thomas

Explanation:

its correct did it on a test

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54 $\frac{m}{s}$

Explanation:

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The number of significant figures in 0.060900 is

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There are <u>5</u> significant figures.

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Kinetic energy depends on which two things

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2 years ago

How many moles of oxygen atoms are in 2 moles of water?

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6 0

3 years ago

Two blocks connected by a light string are being pulled across a frictionless horizontal tabletop by a hanging 16.2-N weight (bl

Artemon [7]

Newton's second law allows us to find the results for the string tensions are:

T₁ = 6.7 N

T₂ = 16.54 N

Newton's second law gives a relationship between force, mass and acceleration of bodies

∑ F = ma

Where the bold letters indicate vectors, F is the force, m the mass and the acceleration.

Free-body diagrams are representations of the forces applied to bodies without the details of them.

The reference system is a coordinate system with respect to which the forces decompose, in this case the x-axis is parallel to the plane and the positive direction in the direction of movement, the y-axis is perpendicular to the plane.

In the attachment we see a free-body diagram of the three-block system.

Let's apply Newton's second law to each body.

Block C

Y-axis

$W_c -T_2 = m_c a$

Block A

X axis

$T_2 - T_1 - W_a_x = m_a a$

Y axis

$N_a - W_a_y = 0$

Block B

X axis

$T_1 - W_b_x = m_b a$

Y axis

$N_b - W_b_y =0$

Let's use trigonometry to find the components of the weight.

Block A

cos θ = $\frac{W_a_y}{W_a}$

sin θ = $\frac{W_a_x}{W_a}$

$W_a_y = W_a cos \theta$

$W_a_x= W_a sin \theta$

Block B

cos θ = $\frac{W_b_y}{W_b}$

sin θ = $\frac{W_b_x}{W_b}$

$W_b_y = W_b cos \theta \\W_b_x = W_b sin \theta$

Let's write our system of equations.

$W_c - T_2 = m_c a \\ T_2 - T_1 - W_a_x = m_a a \\T_1 - W_b_x = m_b a$

Let's find the acceleration of the bodies, adding the equations.

$W_c - W_a_x - W_b_x = ( m_a+m_b+m_c) a\\$

The weight is

W = mg

Let's substitute

$(m_c - m_a -m_b ) g \ sin \theta = ( m_c+m_a+m_b) \ a \\a= \frac{ m_c-m_a-m_b }{ m_a+m_b+m_c} \ g sin \theta$

Indicate ma mass of the block a ma = 1.00 kg, the mass of the block b mb = 2.2 kg and the weight of the block c Wc = 16.2 N, let's find the mass of block c.

m_c = Wc / g

m_c = 16.2 / 9.8

m_c = 1.65 kg

we substitute the values

$a= \frac{1.65 -2.20 -1.00}{1.65+2.20+1.00} \ 9.8 \ sin \theta \\a= -0.3096 sin \theta$

The negative sign indicates that the system is descending, to be able to give a specified value an angle is needed, they assume that the angle of the ramp is 45º

a = - 0.3196 sin 45

a = -0.226 m / s

Taking the acceleration we are going to look for the tensions.

From the equation of block C

$W_c - T_2 = m_c a \\T_2 = m_c ( g-a)\\T_2 = 1.65 ( 9.8 + 0.226)$

T₂ = 16.54 N

From the equation of block B

$T_1 - W_b_x = m_b a\\T_1 = m_b (a + g sin \theta)\\T_1 = 1.00 (-0.226 + 9.8 \ sin 45)$

T₁ = 6.7 N

In conclusion using Newton's second law we can find the results for the string tensions are:

T₁ = 6.7 N

T₂ = 16.54 N

Learn more here: brainly.com/question/20575355

7 0

2 years ago