An anchor weighing 105 lb in water is attached to a chain weighing 3 lb/ft in water. Find the work done to haul the anchor and c
1 answer:
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1) Mass of one copper atom:
2) There are atoms in the cube
3) Mass of the cubical block: 992 kg
Explanation:
1)
We are told here that the mass of one mole of copper is
for
(number of moles)
We also know that the number of atoms inside 1 mole of substance is equal to Avogadro number:
This means that atoms of copper have a mass of M = 64 g. Therefore, we can find the mass of one copper atom by dividing the total mass by the avogadro number:
2)
We are told that the diameter of a copper atom is
We can assume that the atoms are arranged in a cube, and that they are all attached to each other; so the side of the cube can be written as size of one atom multiplied by the number of atom per side:
where
N is the number of atoms (rows) in one side of the cube
Since the side of the cube is
L = 4.8 cm = 0.048 m
We find N:
This is the number of atom rows per side; therefore, the total number of atoms in the cube is
3)
The total mass of the cubical block of copper will be given by the mass of one atom of copper multiplied by the total number of atoms, so:
where:
is the number of atoms in the cube
is the mass of one atom
Therefore, substituting, we find:
So, the mass of the cubical block is 992 kg.
Learn more about mass and density:
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Answer:
43.16°
Explanation:
λ = Wavelength = 1.4×10⁻¹⁰ m
θ₁ = 20°
n can be any integer
d = distance between the two slits
Since for the first bright fringe, n₁ = 1
n₂ = 2 for second order line
The relation between the distance of the slits and the angle through which it is passed is:
dsinθ=nλ
As d and λ are constant
∴ Angle by which the second order line appear is 43.16°