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Anettt [7]
3 years ago
12

Block A, with a mass of 4.0 kg, is moving with a speed of 2.0 m/s while block B , with a mass of 8.0 kg, is moving in the opposi

te direction with a speed of 3.0 m/s. The center of mass of the two block system is moving with velocity of?
Physics
1 answer:
Anon25 [30]3 years ago
5 0
Consider velocity to the right as positive.

First mass:
m₁ = 4.0 kg
v₁ = 2.0 m/s to the right

Second mass:
m₂ = 8.0 kg
v₂ = -3.0 m/s to the left

Total momentum of the system is
P = m₁v₁ + m₂v₂
   = 4*2 + 8*(-3)
  = -16 (kg-m)/s

Let v (m/s) be the velocity of the center of mass of the 2-block system.

Because momentum of the system is preserved, therefore
(m₁+m₂)v= -16
(4+8 kg)*(v m/s) = -16 (kg-m)/s
v = -1.333 m/s

Answer:
The center of mass is moving at 1.33 m/s to the left.
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Answer:

2.4 mm

Explanation:

Given that:

Initial Original length of the wire L = 3 mm

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The stretch of the second wire ΔL'' = ???

Considering the Tension of the system; the Young modulus and the cross sectional remains constant ; as such:

\frac{Y}{Y''} = \frac{FL}{A \Delta L} *\frac{A \Delta L''}{FL''}

1= \frac{L   \Delta L''}{L'' \Delta L}

\Delta L''= \frac{L'' \Delta L  }{L}

\Delta L''= \frac{6 \ m * 1.2 \ mm  }{3 \ m}

\Delta L''=2.4  \ mm

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A person notices a mild shock if the current along a path through the thumb and index finger exceeds 82 µA. Find the maximum all
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Answer:

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Explanation:

Given data

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to find

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