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alexgriva [62]
3 years ago
10

PLEASE HELP!!! ILL GIVE THE BRIANLIEST TO TO WHOEVER ANSWERS CORRECTLY!!!!!!!

Mathematics
1 answer:
Mariulka [41]3 years ago
6 0

Answer:

B

Step-by-step explanation:

The range is the largest number minus the smallest number.

Hope this helps!

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Advanced conversions:
san4es73 [151]

Answer:

Step-by-step explanation:

1). ∵ 1 L = 1000 ml

   ∴ 4 L = 4000 ml

2). ∵ 1 cm = 10 mm

    ∴ 5 cm = 50 mm

3). ∵ 1 mg = 0.1 cg

    ∴ 5 mg = 0.5 cg

4). ∵ 1 ml = 0.001 L

    ∴ 25 ml = 0.025 L

5). ∵ 1 gm = 1000 mg

    ∴ 0.125 gm = 25 mg

6). ∵ 1 ml = 0.001 L

    ∴ 570 ml = 0.57 L

7). ∵ 1 mm = 0.1 cm

    ∴ 135 mm = 13.5 cm

8). ∵ 1 mg = 0.001 g

    ∴ 1820 mg = 1.82 g

9). ∵ 1 g = 100 cg

    ∴ 0.5 g = 50 cg

10). ∵ 1 ml = 0.001 L

     ∴ 0.2385 ml = 0.0002385 L

6 0
3 years ago
Write the slope-intercept form of the equation for the line given the slope and y-intercept (equation: y=mx+b) Slope = 5, y-inte
Rufina [12.5K]

Answer:

y=5x+2

Step-by-step explanation:

Slope formula:

y=mx+b

- m stands for slope

- b stands for y intercept.

Plug the information in:

y=5x+2

3 0
3 years ago
Sorry if l’m posting so many photo but l really just need help for my math class homework
Finger [1]

We have 2 angles that are supplementary, so their sum equals 180⁰.

(4x - 10) + (7x - 8) =180

11x - 18 = 180

11x = 198

x = 18

8 0
3 years ago
Read 2 more answers
Can someone Plzzz help me out???
Vitek1552 [10]

Hello from MrBillDoesMath!


Answer:  3


Discussion:

The perimeter of a polygon is the sum of the side lengths.

Perimeter of top polygon is   (x+2) + 2x + (x + 2) + (4x + 1) =  8x + 5

Perimeter of bottom triangle is   4x + 2x + (3x+2 ) =  9x + 2


The perimeters are the same when

8x + 5 = 9x + 2

Subtract 8x from both sides:

5 = (9x - 8x) + 2   or

5 = x + 2

Subtract 2 from each side to get x = 3:

5 -2 = 3 = x


The perimeter of either figure is 29



Regards, MrB

6 0
3 years ago
Ratio 6 to 5 of 20000
neonofarm [45]

Answer:

24000

Step-by-step explanation:

6/5×20000

=24000

4 0
2 years ago
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