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alexgriva [62]
2 years ago
10

PLEASE HELP!!! ILL GIVE THE BRIANLIEST TO TO WHOEVER ANSWERS CORRECTLY!!!!!!!

Mathematics
1 answer:
Mariulka [41]2 years ago
6 0

Answer:

B

Step-by-step explanation:

The range is the largest number minus the smallest number.

Hope this helps!

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Pepsi [2]

Answer:

She sold 39 tall candies and 52 short candies

Step-by-step explanation:

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3 years ago
Verify the trigonometric identities
snow_lady [41]
1)

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\bf [sin(x)+cos(x)]^2+[sin(x)-cos(x)]^2=2
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[sin^2(x)+2sin(x)cos(x)+cos^2(x)]\\\\+~ [sin^2(x)-2sin(x)cos(x)+cos^2(x)]
\\\\\\
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2)

here we also do the left-hand-side

\bf \cfrac{2-cos^2(x)}{sin(x)}=csc(x)+sin(x)
\\\\\\
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\\\\\\
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3)

here, we do the right-hand-side

\bf \cfrac{cos(x)-sin^2(x)}{sin(x)+cos^2(x)}=\cfrac{csc(x)-tan(x)}{sec(x)+cot(x)}
\\\\\\
\cfrac{csc(x)-tan(x)}{sec(x)+cot(x)}\implies \cfrac{\frac{1}{sin(x)}-\frac{sin(x)}{cos(x)}}{\frac{1}{cos(x)}-\frac{cos(x)}{sin(x)}}\implies \cfrac{\frac{cos(x)-sin^2(x)}{sin(x)cos(x)}}{\frac{sin(x)+cos^2(x)}{sin(x)cos(x)}}
\\\\\\
\cfrac{cos(x)-sin^2(x)}{\underline{sin(x)cos(x)}}\cdot \cfrac{\underline{sin(x)cos(x)}}{sin(x)+cos^2(x)}\implies \cfrac{cos(x)-sin^2(x)}{sin(x)+cos^2(x)}
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3 years ago
Please help me I don’t understand this
Tomtit [17]

Answer:64

Step-by-step explanation:

67

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