Question

Kareem heats a beaker of water to boil. Then he records that the water temperature decreases from 100% C to 19 C in 5 2/5 minutes. What was the charged in temperature each minute?

Answer 1

Given :

Kareem heats a beaker of water to boil. Then he records that the water temperature decreases from 100° C to 19° C in 5 2/5 minutes.

To Find :

What was the charged in temperature each minute.

Solution :

Time taken to reach 19° C :

$T = 5\dfrac{2}{5}= \dfrac{27}{5}\ min$

Now, change in temperature per minute is given by :

$R =\dfrac{19^{o}-100^o}{\dfrac{27}{5}}\\\\R = -15 \ ^oC/ minute$

Therefore, the charged in temperature each minute is -15 °C/minute .

Hence, this is the required solution.