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Ann [662]
2 years ago
12

Calcula la altura de un cono se 235.62cm³ de volumen si el radio de la base mide 5cm​

Mathematics
1 answer:
Ber [7]2 years ago
6 0

Answer:

Datos: r= 24cm. g= 74 cm. ...

- La altura h.

- La generatriz.

- el radio. Que entre ellos forman un triangulo rectángulo siendo la generatriz la hipotenusa y el radio la base, entonces: ...

g²=r²+h² despejando la altura h se tiene que:

h=√g²-r² h= √ (74cm)² - (24 cm)²

es. un paso para que. puedas resolver

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A,B,C, or D? I NEED HELP ON THIS QUESTION
pav-90 [236]

Answer:

d

Step-by-step explanation:

3 0
3 years ago
1. M is the midpoint of LN and O is the midpoint of NP.
Reptile [31]
1. M is the midpoint of LN and O is the midpoint of NP. This makes the triangle MNO equal to half of LNP. Then you can get this equation
MO= (1/2) LP

If you insert MO = 2x +6 and LP = 8x – 20 the calculation would be:
2x+6= (1/2)( 8x-20)
2x+6= 4x-10
2x-4x= -10 - 6
-2x= -16
x=8

2. Centroid is the point that intersects with three median lines of the triangle. The centroid should divide the median lines into 1:2 ratio. In AC lines, A located in the base so A.F:FC would be 1:2

Then, the answer would be:
A.F= 1/(1+2) * AC
A.F= 1/3 * 12= 4

FC= 2/(1+2) * AC
FC= 2/3 * 12= 8

3. Since
∠BAD=∠DAC
∠ABD=∠ACD
AD=AD
The triangle ABD and ACD are similar. You can get this equation
BD=DC
x+8= 3x+12
x-3x= 12-8
-2x=4
x=-2

DC=3x+12= 3(-2) +12= 6

4. Orthocenter made by intersection of triangle altitude
A
BC lines slope would be (-4)-(-1)/1-4= -3/-3= 1. The altitude line slope would be -1, the function would be:
y=-x +a
0= 1+a
a=-1
y=-x-1
B
AC lines slope would be (-4)-(-1)/1-0= -3. The altitude line slope would be 1/3, the function would be:
y=1/3x+a
-1=1/3(4)+a
a=-7/3
y=1/3x - 7/3

C
BC lines slope would be (-1)-(-1)/4 = 0/4. 
The line would be 
0=x+a
a=-1
0=x-1
x=1

y=-x-1 = 1/3x-7/3
-x-(1/3x)=-7/3 +1
-4/3x= -4/3
x=1

y=-x-1
y=-1-1= -2
The orthocenter would be (1,-2)

5. 
a. Circumcenter: the intersection of perpendicular bisector lines<span>
b. Incenter: the intersection of bisector lines
c. Centroid: </span>the intersection of median lines<span>
d. Orthocenter: </span>the intersection of altitude lines
5 0
3 years ago
I need help please?!!
Sveta_85 [38]

Answer:

72

Step-by-step explanation:

8 0
3 years ago
Help please answer fast!!!
pav-90 [236]

Answer:

4 \sqrt{2}

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
After jumping rope for 15 minutes, Jan took a break. If Jan took a break at 3:05 p.M., at what time did she start jumping rope?
Kitty [74]

Answer: 2 : 50 pm

Step-by-step explanation:

If Jan took a break at 3:05 pm and she had been jumping rope for 15 minutes before that, to find the time she started jumping rope, subtract 15 from the current time:

= 3:05 - 15

= 2:50 pm

<em>Jan started jumping rope at 2 : 50 pm </em>

3 0
3 years ago
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