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alexira [117]
3 years ago
5

Find the length of arc AB

Mathematics
2 answers:
julia-pushkina [17]3 years ago
7 0

Answer:

OH HELL NO!

Step-by-step explanation:

tester [92]3 years ago
3 0

Answer:

m\widehat {AB} = 144\degree

m\widehat {ACB} = 216\degree

Step-by-step explanation:

Let the measures of the given arcs be 2x and 3x.

\because m\widehat {AB} \:\&\: m\widehat {ACB} sums up to form a circle.

Therefore,

2x + 3x = 360°

5x = 360°

x = 360°/5

x = 72°

2x = 2*72 = 144°

3x = 3*72° = 216°

\therefore m\widehat {AB} = 144\degree

\& m\widehat {ACB} = 216\degree

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180-96

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Jasmine bought 32 kiwi fruit for $16. IfJasmine has $4, how many kiwi can shebuy?
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7 0
3 years ago
In a certain clinical study, 15% of participants were classified as heavy smokers, 25% as light-smokers, and the rest as non-smo
Natasha_Volkova [10]

Answer:

There is a 28.57% probability that a randomly selected participant who died by the end of the study was a non-smoker.

Step-by-step explanation:

We have the following probabilities:

A 15% probability that a participant is classified as a heavy smoker.

A 25% probability that a participant is classified as a light smoker.

A 100% - 25% - 15% = 60% probability that a participant is classified as a non smoker.

A x% probability that a non smoker dies.

A 3x% probability that a light smoker dies.

A 5x% probability that a heavy smoker dies.

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

This problem is:

What is the probability of the participant being a non-smoker, given that he died?

P(B) is the probability that the participant is a non smoker. So

P(B) = 0.6

P(A/B) is the probability that the participant dies, given that he is a non smoker. So:

P(A/B) = x

P(A) is the probability that the participant dies:

P(A) = P_{1} + P_{2} + P_{3}

P_{1} is the probability that a heavy smoker is selected and that he dies. So:

P_{1} = 0.15*5x = 0.75x

P_{2} is the probability that a light smoker is selected and that he dies. So:

P_{2} = 0.25*3x = 0.75x

P_{3} is the probability that a non-smoker is selected and that he dies. So:

P_{3} = 0.60*x = 0.60x

The probability that a participant dies is:

P(A) = P_{1} + P_{2} + P_{3} = 0.75x + 0.75x + 0.60x = 2.10x

The probability of the participant being a non-smoker, given that he died, is:

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.6x}{2.10x} = \frac{0.6}{2.10} = 0.2857

There is a 28.57% probability that a randomly selected participant who died by the end of the study was a non-smoker.

7 0
3 years ago
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