Answer:
865
Step-by-step explanation:
We have that in 95% confidence level the value of z has a value of 1.96. This can be confirmed in the attached image of the normal distribution.
Now we have the following formula:
n = [z / E] ^ 2 * (p * q)
where n is the sample size, which is what we want to calculate, "E" is the error that is 2% or 0.02. "p" is the probability they give us, 5 out of 50, is the same as 1 out of 10, that is 0.1. "q" is the complement of p, that is, 1 - 0.1 = 0.9, that is, the value of q is 0.9.
Replacing these values we are left with:
n = [1.96 / 0.02] ^ 2 * [(0.1) * (0.9)]
n = 864.36
865 by rounding to the largest number.
Answer:
208
Step-by-step explanation:
{ed}-{3cb}+{4ba}-{2ea} = {(-15)*(-6)} - {3*5*(-2)} + {4*(-2)*4} - {2*(-15)*4}
={90} - {15*(-2)} + {16*(-2)} - {8*(-15)}
= {90} - {-30} + {-32} - {-120}
= 90 (--)30 (+-) 32 (--) 120
= 90 + 30 - 32 + 120
= 120 - 32 + 120
= 88 + 120
= 208

As we have to solve for b, it means we have to isolate b
So first of all subtract
from both sides
So we get

Now we need b , but its b^2 , so we can take square root on both sides.
taking square roots on both sides

Hence option B is correct