The consecutive integers are i, i+1, i+2, i+3.
3 less than sum of the integers
= i + i +1 + i + 2 + i + 3 - 3 = 4i + 3
<span>ratio of their perimeters and the ratio of their areas would be </span>5:9 and 25:81
Answer:
whats the list
Step-by-step explanation:
Answer:
A) log(jk2y = 7log i + 2logk
Step-by-step explanation: