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chubhunter [2.5K]
2 years ago
7

Can I actually get help and not people saying random stuff just for points????

Mathematics
1 answer:
loris [4]2 years ago
8 0
Do you still need it?
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Brett writes a number that is the same distance from o as 6 on a number line but in the opposite direction. What number did bret
photoshop1234 [79]
Well since 6 would be in the oppposite direction it would be turned around. Well this leads to non than any other number 9.

Answer ~ 9
4 0
2 years ago
_________<<<<______free 5 pts lol.
GarryVolchara [31]

Answer:

yes it is true becasue ya so that equals and that is why 5(4 − x) < 3x + 1

Step-by-step explanation:

7 0
3 years ago
2x+4=18 <br> what does 'x' equal?
astra-53 [7]

Answer:

7

Step-by-step explanation:

18-4

=14

÷2

=7.

hoped this helped

5 0
3 years ago
i know this is probably simple but ive forgotten how to do it and i cant find it in my notes help appreciated!
Soloha48 [4]

Answer:

? = 13.6

Step-by-step explanation:

the angle between a tangent and the diameter = 90°

Then the triangle is right with legs 2 × 6 = 12 and 6.4

using Pythagoras' identity in the right triangle.

the square on the hypotenuse is equal to the sum of the squares on the legs , that is

? ² = 12² + 6.4² = 144 + 40.96 = 184.96 ( take square root of both sides )

? = \sqrt{184.96} = 13.6

6 0
2 years ago
A rectangular box has a square base. The combined length of a side of the square base, and the height is 20 in. Let x be the len
aniked [119]

Answer:

a. V = (20-x) x^{2} in^{3}  

b . 1185.185 in^{3}

Step-by-step explanation:

Given that:

  • The height:  20  - x (in )
  • Let x be the length of a side of the base of the box (x>0)

a. Write a polynomial function in factored form modeling the volume V of the box.

As we know that, this is a rectangular box has a square base so the Volume of it is:

V = h *x^{2} in^{3}

<=> V = (20-x) x^{2}  in^{3}

b. What is the maximum possible volume of the box?

To  maximum the volume of it, we need to use first derivative of the volume.

<=> dV / Dx = -3x^{2} + 40x

Let dV / Dx = 0, we have:

-3x^{2} + 40x  = 0

<=> x = 40/3

=>the height h = 20/3

So  the maximum possible volume of the box is:

V = 20/3 * 40/3 *40/3

= 1185.185 in^{3}

7 0
2 years ago
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