Answer:
a) 7/4 b) 5 c) 2
Step-by-step explanation:
Logrithmic Rule for a and b
Let a, M, N be positive real numbers.
a)
logaM - logaN = loga(M/N)
log9(7) - log9(4) = log9 (7/4)
b)
logaM + logaN = logaMN
log2 (x) + log2(9) = log2(45)
x9=45
(x9)/9 = 45/9
x = 5
c)
Change of base formula.
logb(x)=logd(b)/logd(x)
x log6(5) = log6(25) divide each term by log6(5)
x log6(5) / log6(5) = log6(25) / log6(5) Cancel common factor log6(5)
x = log6(25) / log6(5)
x = log6(5^2) / log6(5)
Expand log6(5^2) by moving 2 outside the logarithm.
x = 2log6(5) / log6(5) cancel the like term log6(5)
x = 2
First we need to find the the answer to both the square root of 49 and 9.
The "square root" is a term referring to a number, multiplied by itself (x • x) would be = to your square root.
So for example: Square root of 16 = 4 because 4*4=16
So lets get out numbers:


Now you multiply 3*7 (or 7*3) and you get 21.
Final answer: 21
Answer:
Step-by-step explanation:
Tear this apart piece by piece
15 - 8 = 7
7 * 3 = 21
11 + 21 = 32
Now so far this much is correct. The problem is the next sign. Is it add or is it divide. The only way to resolve it is to do it both ways.
Add 4
32 + 4 = 36
Divide 4
32 / 4 = 8 1/4 = 8
Answer:
A quadratic equation can be written as:
a*x^2 + b*x + c = 0.
where a, b and c are real numbers.
The solutions of this equation can be found by the equation:

Where the determinant is D = b^2 - 4*a*c.
Now, if D>0
we have the square root of a positive number, which will be equal to a real number.
√D = R
then the solutions are:

Where each sign of R is a different solution for the equation.
If D< 0, we have the square root of a negative number, then we have a complex component:
√D = i*R

We have two complex solutions.
If D = 0
√0 = 0
then:

We have only one real solution (or two equal solutions, depending on how you see it)
The answer is B because Chris and three of his friends is 4. Then, each person paid $9 so 4 x 3 = x.