I need help on this someone please answer this.
1 answer:
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Answer:
Step-by-step explanation:
Hello!
Given the probabilities:
P(A₁)= 0.35
P(A₂)= 0.50
P(A₁∩A₂)= 0
P(BIA₁)= 0.20
P(BIA₂)= 0.05
a)
Two events are mutually exclusive when the occurrence of one of them prevents the occurrence of the other in one repetition of the trial, this means that both events cannot occur at the same time and therefore they'll intersection is void (and its probability zero)
Considering that P(A₁∩A₂)= 0, we can assume that both events are mutually exclusive.
b)
Considering that you can clear the intersection from the formula
and apply it for the given events:
c)
The probability of "B" is marginal, to calculate it you have to add all intersections where it occurs:
P(B)= (A₁∩B) + P(A₂∩B)= 0.07 + 0.025= 0.095
d)
The Bayes' theorem states that:
Then:
I hope it helps!
Answer:
Option D.
Step-by-step explanation:
Minimize the objective function P = 5x + 8y for the given constraints.
The related equations of above inequalities are
For ,
x y
0 5
7.5 0
Plot (0,5) and (7.5,0) and join them by straight line.
For ,
x y
0 7.5
5 0
Plot (0,7.5) and (5,0) and join them by straight line.
Check the inequalities for (0,0).
False
False
It means both lines are solid lines and shaded region for each lies opposite side of (0,0).
From the below graph it is clear that the vertices of feasible region are (0,7.5), (3,3), (7.5,0).
Point P = 5x + 8y
(0,7.5) P=5(0)+8(7.5)=60
(3,3) P=5(3)+8(3)=15+24=39
(7.5,0) P=5(7.5)+8(0)=37.5 (Minimum)
So, minimum value is 37.5.
Therefore, the correct option is D.
