X/2 +3y = 6 . . . . . . . . starting point
x/2 = 6 -3y . . . . . . . . subtract terms that don't have x
x = 2(6 -3y) . . . . . . . . multiply by the inverse of the x-coefficient
x = 12 -6y . . . . . . . . . expand if you like
3y = 6 -x/2 . . . . . . . . subtract terms that don't have y
y = (6 -x/2)/3 . . . . . . . multiply by the inverse of the y-coefficient
y = 2 -x/6 . . . . . . . . . expand if you like
Sorry i didn’t understood the question
h^2 - 12h + 20 can be factored to:
(h-10)(h-2)
These cannot be zero so, h cannot be 10 or 2.
Answer:
I think it might be data and range
Step-by-step explanation:
the answer is at the top
