He equation of a parabola is x = -4(y-1)^2. What is the equation of the directrix?
<span>You may write the equation as </span>
<span>(y-1)^2 = (1) (x+4) </span>
<span>(y-k)^2 = 4p(x-h), where (h,k) is the vertex </span>
<span>4p=1 </span>
<span>p=1/4 </span>
<span>k=1 </span>
<span>h=-4 </span>
<span>The directrix is a vertical line x= h-p </span>
<span>x = -4-1/4 </span>
<span>x=-17/4 </span>
<span>------------------------------- </span>
<span>What is the focal length of the parabola with equation y - 4 = 1/8x^2 </span>
<span>(x-0)^2 = 8(y-4) </span>
<span>The vertex is (0,4) </span>
<span>4p=8 </span>
<span>p=2 (focal length) -- distance between vertex and the focus </span>
<span>------------------------------- </span>
<span>(y-0)^2 = (4/3) (x-7) </span>
<span>vertex = (7,0) </span>
<span>4p=4/3 </span>
<span>p=1/3 </span>
<span>focus : (h+p,k) </span>
<span>(7+1/3, 0)</span>
Answer:
To transform from polar coordinates into Cartesian coordinates we have:
x = r x cos(theta)
y = r x sin(theta)
r^2 = x^2 + y^2
=> r = 2*cos(theta)
<=> r = 2*(x/r)
<=> 2x = r^2
<=> 2x = x^2 + y^2
Hope this helps!
:)
Answer:
1. 432
2. 30
3. 1875
4. 250
Step-by-step explanation:
To isolate the variable means to have it by itself on one side of the equation, where the variable equals an expression.
To isolate 
, we will need to remove the variables and other terms "connected" to the variable:
By dividing terms "connected" to our variable, we have isolated it one side of the equation.
Square feet because it is an ideal unit to measure rooms.
