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inn [45]
3 years ago
11

An article describes a study in which a new type of ointment was applied to forearms of volunteers to study the rates of absorpt

ion into the skin. Eight locations on the forearm were designated for ointment application. The new ointment was applied to six locations, and a control was applied to the other two. How many different choices were there for the six locations to apply the new ointment
Mathematics
1 answer:
irinina [24]3 years ago
7 0

Answer:

There were 28 different choices for the six locations to apply the new ointment

Step-by-step explanation:

The order in which the location are chosen is not important, which means that we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Two events, A and B are independent, if:

P(A \cap B) = P(A)P(B)

How many different choices were there for the six locations to apply the new ointment?

Six locations from a set of 8. So

C_{8,6} = \frac{8!}{6!2!} = 28

There were 28 different choices for the six locations to apply the new ointment

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Select the correct answer from each drop-down menu.
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3 years ago
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The admission fee is $1.50 for children and $4.00 for adults. If 2700 people enter and $7800 is collected how many children and
mash [69]

Number of children attended is 1200 and number of adults attended is 1500

<h3><u>Solution:</u></h3>

Given that,

Admission fee for each children = $ 1.50

Admission fee for each adult = $ 4.00

Let "c" be the number of children attended

Let "a" be the number of adults attended

Given that 2700 people enter and $7800 is collected

Number of children attended + number of adults attended = 2700

c + a = 2700  -------- eqn 1

Also given that $7800 is collected

Number of children attended x Admission fee for each children + number of adults attended x Admission fee for each adult = 7800

c \times 1.50 + a \times 4 = 7800

1.5c + 4a = 7800 -------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "a" and "c"

From eqn1,

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Substitute eqn 3 in eqn 2

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Therefore from eqn 3,

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Therefore number of children attended = c = 1200

number of adults attended = a = 1500

3 0
3 years ago
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