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alexira [117]
3 years ago
6

A rectangular box has the dimensions shown in the diagram. The volume of the box is given by the function V(x) = x^3 – 4x, where

x is the height in inches. What is the height of the box if the volume is 15 in.^3?
Mathematics
1 answer:
madreJ [45]3 years ago
4 0

Answer:

length, width, and height are (b+2), (b-2), (b+3)

Step-by-step explanation:

Doing what the problem statement tells you to do, you get ...

 (b^3 +3b^2) -(4b +12)

 = b^2(b +3) -4(b +3) . . . . . factor each pair of terms

 = (b^2 -4)(b +3) . . . . . . . . . write as a product

 = (b -2)(b +2)(b +3) . . . . . . use the factoring of the difference of squares

The three factors are (b-2), (b+2), and (b+3). We have no clue as to how to associate those with length, width, and height. We just know these are the dimensions of the box.

Step-by-step explanation:

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A 5 inch tall bamboo shoot doubles in height every 3 days. If the equation y=ab exponent X,where x is the number of doubling per
Andreyy89
 "x = 2; a = 5; b = 3" A 5 inch tall bamboo shoot doubles in height every 3 days. If the equation y=ab^x, where x is the number of doubling periods, represents the height of the bamboo shoot.
8 0
3 years ago
An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s
Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, s=120\ ft/s

The height 'h' of the debris above the ground is given as:

h(t)=-16t^2+120t

As per question, h(t)=56\ ft. Therefore,

56=-16t^2+120t

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0

Using quadratic formula to solve for 't', we get:

t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s

Therefore, the debris will reach a height of 56 ft twice.

When time t=0.5\ s during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at t=7\ s, the height is 56 ft.

5 0
3 years ago
Which equation represents a line that passes through (-2, 4) and has a slope of 2/5
Ronch [10]

An equation represents a line that passes through (-2, 4) and has a slope of 2/5 is y-4 = 2/5(x+2)

<h3>Equation of a line</h3>

The equation of a line in point-slope form is expressed as;

y-y1 = m(x - x1)

where

m is the slope

(x1, y1) is any pint on the line

Substitute the given parameter

y - 4 = 2/5(x-(-2))

y-4 = 2/5(x+2)

Hence an equation represents a line that passes through (-2, 4) and has a slope of 2/5 is y-4 = 2/5(x+2)

Learn more on equation of a line here: brainly.com/question/13763238

#SPJ1

3 0
2 years ago
Pls help or your mom will kidnap you
andrey2020 [161]
I think it is option 1 sorry if wrong
3 0
3 years ago
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Write a ratio to compare 54 feet to 84 feet
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54:84___(÷2)
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