Will mark brainliest!!!Using sin in math solve the one circled in green
1 answer:
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Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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Answer:
Hey there!
The correct option is A
How ?
- -5 represents x' ,which tells us that the respected option is in Left side
- 4 represents y, which tells us that the respective option is upward side
- and Option A is at left and upward side
hope it helped you:)
