Well in the technical sense, we normally establish these as solutions, but in a practical world it is common to call them solutions. Although this is all true, I refer to this beautiful item of chemistry as the sir mix a lot of chemicals
Answer:
149.79
Explanation:
Formula
Joules = m * c * delta (t)
Givens
J = 28242
m = ?
c = 4.19
Δt = 63 - 18 = 45
Solution
28242 = m * 4.19 * 45
28242 = m * 188.55
m = 28242 / 188.55
m = 149.79
Answer:
Explanation:
pH = pKa + log [ CH₃COO⁻ ] / [CH₃COOH ]
5.36 = 4.86 + log [ CH₃COO⁻ ] / [CH₃COOH ]
log [ CH₃COO⁻ ] / [CH₃COOH ] = .5
[ CH₃COO⁻ ] / [CH₃COOH ] = 3.16
moles of CH₃COOH = .680 x .9 = .612 M
Let x mole of KOH is required
x /( .612 - x ) = 3.16
x = 1.933 - 3.16 x
x = .46488
.46488 moles of KOH will be required
volume required be V
v x 2.62 = .46488
v = .1774 L
= 177.4 mL
177.4 mL of 2.62 M KOH will be required .
To find the molarity of the compound, simply determine the molar mass of MgCl2 and then convert 50 g to moles using the molar mass of the compound. Then convert 150 ml to L = 0.15 L
Then divide the moles amount by the volume in L.
