Question

Hi, please I need help

Answer 1

The mass of ethanol (alcohol) = 538.016 g

Further explanation

Given

Reaction

C₁₂H₂₂O₁₁(aq)+H₂O(I) = CH₃CH₂OH(aq)+CO₂(g)

1 kg of sugar = 1000 g

Required

The mass of ethanol

Solution

Balanced equation

C₁₂H₂₂O₁₁(aq)+H₂O(I) = 4CH₃CH₂OH(aq)+4CO₂(g)

mol of sugar (MW = 12.12+22.1+11.16=342 g/mol) :

mol = mass : MW

mol = 1000 g : 342 g/mol

mol = 2.924

From the equation, mol ratio of C₁₂H₂₂O₁₁ : CH₃CH₂OH = 1 : 4, so mol ethanol =

= 4 x mol sugar

= 4 x 2.924

= 11.696

Mass of ethanol(MW=46 g/mol) :

mass = mol x MW

mass = 11.696 x 46

mass = 538.016 g