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Andrei [34K]
3 years ago
13

What is molarity of 50.0 g of mgcl2 dissolved in 150 ml of solution?

Chemistry
1 answer:
Ivahew [28]3 years ago
8 0
To find the molarity of the compound, simply determine the molar mass of MgCl2 and then convert 50 g to moles using the molar mass of the compound. Then convert 150 ml to L = 0.15 L

Then divide the moles amount by the volume in L.
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Calculate each of the following:<br> (b) Mass % of Mn in potassium permanganate
Brilliant_brown [7]

Mass percent is the estimation of the mass of the element in a compound in percentage form. The mass % of manganese (Mn) in potassium permanganate is 34.76 %.

<h3>What is the mass percentage?</h3>

The mass percentage is defined by dividing the mass of the element by the molecular mass of the compound followed by multiplying it by 100%. It is given as,

Mass % =  (Atomic Mass of element ÷ Molecular Mass) × 100

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Substituting values to calculate mass % as:

% Mn  =  (Atomic Mass of Mn ÷ Molecular Mass of KMnO₄) × 100

= (54.94 g/mol ÷ 158.034 g/mol) × 100

= 34.76 %

Therefore, 34.76% Mn is present in KMnO₄.

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3 0
2 years ago
A 1 liter solution was diluted to a molarity of 2 M by bringing the volume up to 4 liters. What was the initial molarity of the
kompoz [17]

Answer:

8.0 mol/L

Explanation:

To do this problem you need to use C₁V₁=C₂V₂. C=concentration and V=volume. (Note: you dont want to use M₁V₁=M₂V₂ because this is measuring mass not concentration).

So, V₁= 1.0L

C₂=2 Mol/L

V₂= 4 L

C₁ is unknown.

you would plug this equation in like this:

(C₁)(1.0 L)=(2.0 Mol/L)(4.0L).

Do algebra to get C₁ alone.

C₁=\frac{(2.0 mol/L)(4.0L)}{1.0L} =8.0 mol/L

The liters cancel out and you are left with mol/L or M

I hope this helps! good luck :)

5 0
2 years ago
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