Due in 10 minutes so

Im bad at money :/ do please help me

Semenov [28]

The third answer

1 quarter, 6 dimes, 1 nickel, 7 pennies

6 0

3 years ago

NAME: A

Lelu [443]

Answer:

4/5

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Suppose that a researcher is designing a survey to estimate the proportion of adults in your state who oppose a proposed law tha

irinina [24]

Answer:

$n=\frac{0.5 (1-0.5)}{(\frac{0.02}{1.96})^2}= 2401$

So without prior estimation for the population proportion, using a confidence level of 95% if we want a margin of error about 2% we need al least a sample size of 2401.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

Solution to the problem

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

If solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

The margin of error desired for this case is $ME= \pm 0.02$ equivalent to 2% points

For this case we need to assume a confidence level, let's assume 95%. And since we don't have prior estimation for the population proportion of interest the best value to do an approximation is $\hat p =0.5$

In order to find the critical value we need to take in count that we are finding the margin of error for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=\pm 1.96$

Now we have all the values needed and if we replace into equation (b) we got:

$n=\frac{0.5 (1-0.5)}{(\frac{0.02}{1.96})^2}= 2401$

So without prior estimation for the population proportion, using a confidence level of 95% if we want a margin of error about 2% we need al least a sample size of 2401.

5 0

3 years ago

Determine the first expression to evaluate in each problem (3+3)+6÷3+6

hram777 [196]

To know what to do first in a math problem we look to order of operations... PEMDAS stands for parentheses, exponents, multiplication, division, addition, and subtraction. So to begin we look for parentheses... do we have any? Why, yes, yes we do. Let's work!

(3+3) + 6 / 3 + 6 =

Add 3+3 in the parentheses. Since there is nothing else, the parentheses can go away.

6 + 6 / 3 + 6 =

Now, any exponents? Nope... Multiplication? Nope... division? Yes! Let's go!

6 + 2 + 6 =

Now all we have left is addition... Go for it!

8 + 6 = 14

Done!

3 0

3 years ago

Read 2 more answers

Engineers want to design seats in commercial aircraft so that they are wide enough to fit 99% of all males. (accommodating 100

Helga [31]

Hip Breadths and Aircraft Seats
Engineers want to design seats in commercial aircraft so that they are wide enough to fit 98% of all males. (Accommodating 100% of males would be too expensive.) Men have hip breadths that are normally distributed with a mean of 14.4 in. and a standard deviation of 1.0 in. Find P 98. That is, find the hip breadth for men that separates the smallest 98% from the largest 2%.

7 0

3 years ago